Calculate the pH of a 0.154 M solution of ethylenediamine (H2NCH2CH2NH2). The pKa values for the acidic form of ethylenediamine (H3 NCH, CH, NH) are 6.848 (pKa1) and 9.928 (pKa2). pH = 11.51 Correct Answer Calculate the concentration of each form of ethylenediamine in this solution at equilibrium. 4.12 x10-3 [H2NCH2CH2NH3] = = Incorrect Answer [HNCH2CH2NH3] = 7.05 x10-8 Correct Answer M M
Calculate the pH of a 0.154 M solution of ethylenediamine (H2NCH2CH2NH2). The pKa values for the acidic form of ethylenediamine (H3 NCH, CH, NH) are 6.848 (pKa1) and 9.928 (pKa2). pH = 11.51 Correct Answer Calculate the concentration of each form of ethylenediamine in this solution at equilibrium. 4.12 x10-3 [H2NCH2CH2NH3] = = Incorrect Answer [HNCH2CH2NH3] = 7.05 x10-8 Correct Answer M M
Introductory Chemistry: A Foundation
8th Edition
ISBN:9781285199030
Author:Steven S. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Donald J. DeCoste
Chapter16: Acids And Bases
Section: Chapter Questions
Problem 42QAP
Related questions
Question
mt.1
![Calculate the pH of a 0.154 M solution of ethylenediamine (H2NCH2CH2NH2). The pKa values for the acidic form of
ethylenediamine (H3 NCH, CH, NH) are 6.848 (pKa1) and 9.928 (pKa2).
pH =
11.51
Correct Answer
Calculate the concentration of each form of ethylenediamine in this solution at equilibrium.
4.12 x10-3
[H2NCH2CH2NH3] =
=
Incorrect Answer
[HNCH2CH2NH3] =
7.05 x10-8
Correct Answer
M
M](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F5c9df204-0052-4906-a777-b483a7f67b84%2F2a1c3c1d-aeb5-4429-b172-0190f85afdf9%2F5pn8tui_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Calculate the pH of a 0.154 M solution of ethylenediamine (H2NCH2CH2NH2). The pKa values for the acidic form of
ethylenediamine (H3 NCH, CH, NH) are 6.848 (pKa1) and 9.928 (pKa2).
pH =
11.51
Correct Answer
Calculate the concentration of each form of ethylenediamine in this solution at equilibrium.
4.12 x10-3
[H2NCH2CH2NH3] =
=
Incorrect Answer
[HNCH2CH2NH3] =
7.05 x10-8
Correct Answer
M
M
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