Answered: Calculate the pH during the titration…

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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Calculate the pH during the titration of 50.00 mL of 0.0500 M NaOH with 0.1000 M HCl after the addition of the following volumes of titrant: a) 0.00 mL b) 24.50 mL c) 25.00 mL d) 25.50 mL

This question was answered but I am not sure of the answer because the formula includes the division of the equation by the volume of base + volume of acid.

I was wondering if it is really as is or something is really lacking.

I attached a previous solution to a similar problem.

To determine the equilibrium concentration of H30*
H30+= original moles acid-total moles base added
volume of acid (L)+volume of base (L)
volume of base in liters =25.00 mL x T00 mL.
IL-0.02500 L
0.150 mol OH
total mol OH added = 0.02500 mL x
=0.00375L mol OH
IL
[H3O+] = 0.00750 mol -0.00375 mol
!=0.0500 M
0.05000L.+0.02500 1.
pH=-log [H3O*]
=-log(0.050)
= 1.30

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