Calculate the pH and PO, concentration in 2.25 M phosphoric acid (H;PO.) solution?H3PO,(aq) + H2O(1) = H;O^(aq) + H,PO, (aq) Ka1 = 7.1×10H2PO, (aq) + H,O(1) = H,O*(aq) + HPO,² (aq) K, 2 = 6.3×10¯HPO (aq) + H,O(1) = H;O*(aq) + PO," (aq) K,3 = 4.2×101³O a. pH = 0.948; [PO,"] = 2.38×10 *° M.onO b. pH = 0.875; [PO,"] = 1.99×10¬1º MOc pH = 0.986; [PO, 1 = 2.56×10¬1ª MO d. pH = 0.924; [PO,"] = 2.22×10¬1° MO e. pH = 0.898; [PO,1 = 2.09×10 1º M

Since H3PO4(aq) is a triprotic acid, it undergoes dissociation 3 times to form 3H+(aq) and…

Calculate the pH and PO, concentration in 2.25 M phosphoric acid (H;PO,) solution? H,PO.(aq) + H,0(1) = H;O*(aq) + H2PO, (aq) K, = ¯ H&PO (aq) + H;O(1) = H,O*(aq) + HPO,*"(aq) K, 2 = 6.3×10¯º HPO (aq) + H,O(1) = H;O^(aq) + PO, (aq) Ka3 = 4.2×10¬" 7.1x10 %3D O a. pH = 0.948; [PO,"] = 2.38×10 1º M. %3D O b. pH = 0.875; [PO,"]= 1.99×10¬1º M Oc. pH = 0.986; [PO,"1 = 2.56×101º M O d. pH = 0.924; [PO,"1 = 2.22× 101º M O e. pH = 0.898; [PO, ] = 2.09×10*° M

Calculate the pH and PO, concentration in 2.25 M phosphoric acid (H;PO,) solution? H,PO.(aq) + H,0(1) = H;O(aq) + H2PO, (aq) K, = ¯ H&PO (aq) + H;O(1) = H,O(aq) + HPO,"(aq) K, 2 = 6.3×10¯º HPO (aq) + H,O(1) = H;O^(aq) + PO, (aq) Ka3 = 4.2×10¬" 7.1x10 %3D O a. pH = 0.948; [PO,"] = 2.38×10 1º M. %3D O b. pH = 0.875; [PO,"]= 1.99×10¬1º M Oc. pH = 0.986; [PO,"1 = 2.56×101º M O d. pH = 0.924; [PO,"1 = 2.22× 101º M O e. pH = 0.898; [PO, ] = 2.09×10° M

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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