Use the following equilibria 2CH4(g) C2Hg(g) + H2(g) K1 = 9.5 × 10-13 CH4(g) + H20(g) CH3OH(g) + H2(g) Kcz = 2.8 × 10-21 to calculate the value of Ke for the following reaction: 2CH3OH(g) + H2(g) - C2Hg(g) + 2H20(g)

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Chapter1: Chemical Foundations
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**Equilibrium Calculations for Reaction Kc'**

In this exercise, we use two given equilibrium reactions to calculate the equilibrium constant, \( K_c' \), for a third reaction.

1. **Given Equilibria:**

   - **Reaction 1:**
     \[
     2\text{CH}_4(g) \rightleftharpoons \text{C}_2\text{H}_6(g) + \text{H}_2(g) \quad K_{c1} = 9.5 \times 10^{-13}
     \]

   - **Reaction 2:**
     \[
     \text{CH}_4(g) + \text{H}_2\text{O}(g) \rightleftharpoons \text{CH}_3\text{OH}(g) + \text{H}_2(g) \quad K_{c2} = 2.8 \times 10^{-21}
     \]

2. **Target Reaction for Calculation:**

   - **Reaction:**
     \[
     2\text{CH}_3\text{OH}(g) + \text{H}_2(g) \rightleftharpoons \text{C}_2\text{H}_6(g) + 2\text{H}_2\text{O}(g)
     \]

3. **Calculation Required:**
   
   - Calculate \( K_c' \) for the above reaction using the provided equilibrium constants.

**Note:** Apply principles of chemical equilibrium and algebraic manipulation to find \( K_c' \) based on \( K_{c1} \) and \( K_{c2} \).

**Diagram Explanation:**

There are no diagrams or graphs accompanying this text.

**Equation Box:**
\[ K_c' = \boxed{} \] 

Use the values and relationships of the given equilibria to solve for the unknown \( K_c' \).
Transcribed Image Text:**Equilibrium Calculations for Reaction Kc'** In this exercise, we use two given equilibrium reactions to calculate the equilibrium constant, \( K_c' \), for a third reaction. 1. **Given Equilibria:** - **Reaction 1:** \[ 2\text{CH}_4(g) \rightleftharpoons \text{C}_2\text{H}_6(g) + \text{H}_2(g) \quad K_{c1} = 9.5 \times 10^{-13} \] - **Reaction 2:** \[ \text{CH}_4(g) + \text{H}_2\text{O}(g) \rightleftharpoons \text{CH}_3\text{OH}(g) + \text{H}_2(g) \quad K_{c2} = 2.8 \times 10^{-21} \] 2. **Target Reaction for Calculation:** - **Reaction:** \[ 2\text{CH}_3\text{OH}(g) + \text{H}_2(g) \rightleftharpoons \text{C}_2\text{H}_6(g) + 2\text{H}_2\text{O}(g) \] 3. **Calculation Required:** - Calculate \( K_c' \) for the above reaction using the provided equilibrium constants. **Note:** Apply principles of chemical equilibrium and algebraic manipulation to find \( K_c' \) based on \( K_{c1} \) and \( K_{c2} \). **Diagram Explanation:** There are no diagrams or graphs accompanying this text. **Equation Box:** \[ K_c' = \boxed{} \] Use the values and relationships of the given equilibria to solve for the unknown \( K_c' \).
At 25°C, \( K_c = 1 \times 10^{-85} \) for the reaction

\[ 7IO_3^-(aq) + 9H_2O + 7H^+(aq) \rightleftharpoons I_2(aq) + 5H_5IO_6(aq) \]

What is the value of \( K_c \) for the following reaction?

\[ I_2(aq) + 5H_5IO_6(aq) \rightleftharpoons 7IO_3^-(aq) + 9H_2O + 7H^+(aq) \]

\( K_c = \) _______
Transcribed Image Text:At 25°C, \( K_c = 1 \times 10^{-85} \) for the reaction \[ 7IO_3^-(aq) + 9H_2O + 7H^+(aq) \rightleftharpoons I_2(aq) + 5H_5IO_6(aq) \] What is the value of \( K_c \) for the following reaction? \[ I_2(aq) + 5H_5IO_6(aq) \rightleftharpoons 7IO_3^-(aq) + 9H_2O + 7H^+(aq) \] \( K_c = \) _______
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