Calculate the p H of the diprotic acid H2 A (such as H2 SO4) where the dissociation of the first H is strong and the dissociation of the second H is weak but the 5% rule does not apply (K2 is too large relative to the initial concentration of H Aminus). Step 1: H2 A + H2 O – H Aminus + H3 Oplus where K1 is large Step 2: H Aminus + H2 O = A² minus + H3Oplus K2 = 0.012 Assume the initial concentration of H2A is 0.0133 M.

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Calculate the pH of the diprotic acid H₂A (such as H₂SO₄) where the dissociation of the first H is strong and the dissociation of the second H is weak but the 5% rule does not apply (K₂ is too large relative to the initial concentration of HA⁻).

**Step 1**: H₂A + H₂O → HA⁻ + H₃O⁺ where K₁ is large

**Step 2**: HA⁻ + H₂O ⇌ A²⁻ + H₃O⁺, K₂ = 0.012

Assume the initial concentration of H₂A is 0.0133 M.

**Hint**: The H₃O⁺ concentration is not zero when setting up your ICE table for step 2 and be sure to consider the total molarity of H₃O⁺ when calculating the pH.
Transcribed Image Text:Calculate the pH of the diprotic acid H₂A (such as H₂SO₄) where the dissociation of the first H is strong and the dissociation of the second H is weak but the 5% rule does not apply (K₂ is too large relative to the initial concentration of HA⁻). **Step 1**: H₂A + H₂O → HA⁻ + H₃O⁺ where K₁ is large **Step 2**: HA⁻ + H₂O ⇌ A²⁻ + H₃O⁺, K₂ = 0.012 Assume the initial concentration of H₂A is 0.0133 M. **Hint**: The H₃O⁺ concentration is not zero when setting up your ICE table for step 2 and be sure to consider the total molarity of H₃O⁺ when calculating the pH.
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