An important part of acid/base chemistry is neutralization, or when an acid or a base is completely used up during a reaction. Assume the reaction below goes to completion. H₂CO3(aq) Nat is a [Select] [Select] +Na+ OH(aq) → Na+ HCO3(aq) + H₂0 (1) There is the conjugate base, and H₂O is the [Select] a , H₂CO3 is the OH is the [Select] [Select] stochiometric ratio between NaOH and H₂CO3. Therefore, if we have 5 moles of NaOH, we need [ Select] moles of H₂CO3 for neutralization. HCO3 is If we have 5 mL of 1 M NaOH and add 2.5 mL of 2 M H₂CO3, the acid is the limiting reagent and is therefore [Select] If we have 10 mL of 0.1 M NaOH and add 16 mL of 0.05 M H₂CO3, the acid is [Select] and is therefore [Select] If we have 2 mL of 5 M NaOH and add 5 mL of 3 M H₂CO3, the acid is [ Select] and is therefore [Select]

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An important part of acid/base chemistry is neutralization, or when an acid or a base
is completely used up during a reaction.
Assume the reaction below goes to completion.
+Na+ OH(aq)
H₂CO3(aq)
Nat is a [Select]
[Select]
→ Na+ HCO3(aq) + H₂0 (1)
H₂CO3 is the
OH is the [Select]
the conjugate base, and H₂O is the [Select]
There is a [Select]
H₂CO3. Therefore, if we have 5 moles of NaOH, we need
[Select]
stochiometric ratio between NaOH and
moles of H₂CO3 for neutralization.
HCO3 is
If we have 5 mL of 1 M NaOH and add 2.5 mL of 2 M H₂CO3, the acid is the limiting
reagent and is therefore [Select ]
If we have 10 mL of 0.1 M NaOH and add 16 mL of 0.05 M H₂CO3, the acid is
[Select]
and is therefore [Select]
If we have 2 mL of 5 M NaOH and add 5 mL of 3 M H₂CO3, the acid is
[ Select ]
and is therefore [Select]
Transcribed Image Text:An important part of acid/base chemistry is neutralization, or when an acid or a base is completely used up during a reaction. Assume the reaction below goes to completion. +Na+ OH(aq) H₂CO3(aq) Nat is a [Select] [Select] → Na+ HCO3(aq) + H₂0 (1) H₂CO3 is the OH is the [Select] the conjugate base, and H₂O is the [Select] There is a [Select] H₂CO3. Therefore, if we have 5 moles of NaOH, we need [Select] stochiometric ratio between NaOH and moles of H₂CO3 for neutralization. HCO3 is If we have 5 mL of 1 M NaOH and add 2.5 mL of 2 M H₂CO3, the acid is the limiting reagent and is therefore [Select ] If we have 10 mL of 0.1 M NaOH and add 16 mL of 0.05 M H₂CO3, the acid is [Select] and is therefore [Select] If we have 2 mL of 5 M NaOH and add 5 mL of 3 M H₂CO3, the acid is [ Select ] and is therefore [Select]
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