Calculate the number of milliliters of 0.702 M NaOH required to precipitate all of the Ca²+ ions in 132 mL of 0.464 M Ca(NO3)2 solution as Ca(OH)2. The equation for the reaction is: Ca(NO3)2 (aq) + 2NaOH(aq) → Ca(OH)2 (s) + 2NaNO3(aq) Volume = mL
Calculate the number of milliliters of 0.702 M NaOH required to precipitate all of the Ca²+ ions in 132 mL of 0.464 M Ca(NO3)2 solution as Ca(OH)2. The equation for the reaction is: Ca(NO3)2 (aq) + 2NaOH(aq) → Ca(OH)2 (s) + 2NaNO3(aq) Volume = mL
Introductory Chemistry: A Foundation
9th Edition
ISBN:9781337399425
Author:Steven S. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Donald J. DeCoste
Chapter15: Solutions
Section: Chapter Questions
Problem 121AP: Calcium carbonate, CaCO3, can be obtained in a very pure state. Standard solutions of calcium ion...
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Transcribed Image Text:Calculate the number of milliliters of 0.702 M
NaOH required to precipitate all of the
Ca²+ ions in 132 mL of 0.464 M
Ca(NO3)2 solution as
Ca(OH)2. The equation for the reaction is:
Ca(NO3)2(aq) + 2NaOH(aq) → Ca(OH)2 (s) + 2NaNO3(aq)
Volume =
mL

Transcribed Image Text:In the laboratory you dissolve 12.6 g of iron (III) nitrate
in a volumetric flask and add water to a total volume of 250
mL.
What is the molarity of the solution?
M.
What is the concentration of the iron(III) cation?
M.
What is the concentration of the nitrate anion?
M.
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