Calculate the Moment About the Point A -20"- 5 lb 40 N D 1.5 m 40 N 4.5 m A 15 lb. 150 mm 52 N 5 12 100 mm 15 lb. 26 lb. 12 5 34 lb. 13 8 15 77777 36 lb.
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- The following diagram corresponds to questions 1 to 3. A beam rests on two sharp edges as shown on the image. The beam has a length of 7,50 m and a mass of 4,25 kg. Object 1 has a mass of 1,50 kg; object 2 has a mass of 2,35 kg. Point P is 0,50 m form the center of the beam. CG 1. How much is the torque done by object 1 around point P? A. 55,2 N*m B. 7,36 N*m C. 62,5 N*m D. Object 1 doesn't exert a torque. 2. How much is the torque done by the force of gravity of the beam around point P? A. 20,8 N*m N-m ך177 .B C. 156 N*m D. 313 N*m 3. If you needed to cancel the nomal forces of the two objects, where you should place object 2? The axis of rotation is point P. A. 3,30 m from point B. 9,18 m from point P C. 5,69 m from point P D. 3,62 m from point PPlease give the correct handwritten solution. Don't copy from othersites. Solution must be handwritten onlyHelp!! Don’t copy last posted question
- FL y b C Z Determine the moment about O due to the force F shown, the magnitude of the force F = 76.0 lbs. Note: Pay attention to the axis. Values for dimensions on the figure are given in the following table. Note the figure may not be to scale. Variable Value a 1.90 ft b 2.80 ft с 2.60 ft d 2.30 ft Mo 144 ft-lb = -212 × 1 + xk) ☑+212Express the 40 lb force in the rope from point A to point C in cartesian format. Point C is in the x-y plane and at an angle of 20 degrees from the y axis as shown. 4 ft 20 lb A B 3 ft X 40 lb Z 2 ft 1.5 ft 4.87i+27.6j - 28.5k lb -4.87i+27.6j + 28.5k lb -4.87i+27.6j - 28.5k lb 4.87i+22.8j - 32.5k lb 2 ft 20 y C2/48 Calculate the moment MA of the 200-N force about point A by using three scalar methods and one vec- tor method. 200 N 7-A/1Y 15° B 280 mm A 400 mm
- F y b C 10 Z Determine the moment about O due to the force F shown, the magnitude of the force F = 76.0 lbs. Note: Pay attention to the axis. Values for dimensions on the figure are given in the following table. Note the figure may not be to scale. Variable Value a 1.90 ft b 2.80 ft с 2.60 ft d 2.30 ft Mo = lb + k) ft-Problem 3. What is the moment of the 1.4 kN force along the direction of the 1.0 kN force? Express your answer as a magnitude and sketch the direction of rotation about the axis defined by the 1.0 kN force TIGBAO TK 1.0KN X 539 indi 21 150 mm 195 mm 2 4 160 mm 21% ARD 19TO 1.4 kN MEBIRT 0 DAW ITOM 00 1400Add the following forces to find the resultant force. V1 = 150 g @ 470 V2 = 550 @ 324° V3 = 350 g @ 215° V4 = 250 @ 172° V5 = 450 g @ 285°
- 6 in 60° 20 in Statics Instructor A vertical force of P = 100 lb is required to remove the nail at C from the board. Determine the magnitude of the moment about B exerted by the 100 lb vertical force. Draw a free body diagram for the system. Then, use what you know about moments to solve for Mp What is the magnitude of the moment at point B due to P if P = 100 lb and 9 = 10"? Round to the nearest whole number. Enter a response then click Submit below lb inFor multiple choice, choose the best answer. Show all work: indicate your plan and draw FBD's (Free Body Diagrams), write/label (symbolic) equations (e.g., ZFx = 0) before writing numeric equations, box answers. 1. What is the moment of the 12 N force about point A (MA)? 3 N-m 36 N-m a. b. C. 12/3 N-m d. 7 N-m F = 12 N d = 3 mGO 321 3 in F1 F2 a F3 A d F4 F5 Consider the following values: - a = 25 m; b = 5 m; c = 25 m; d = 5 m; F1 = 7 kN; F2 = 8 kN; F3 = 9 kN; F4 = 10 kN; F5 = 11 kN; a = 30°, 0 = 60° , B = 30° 1] What is the resultant moment of the five forces acting on the rod about point A? a) - 158 kN.m b) 127 kN.m c) 146 kN.m d) - 103 kN.m e) 241 kN.m f) - 171 kN.m 2] What is the resultant moment of the five forces acting on the rod about point B? a) 98.8 kN.m b) - 291.7 kN.m c) 311.6 kN.m d) – 264.6 kN.m e) 354.2 kN.m f) - 242.5 kN.m 3] What is the resultant moment of the five forces acting on the rod about point C? a) 86.7 kN.m b) - 141.1 kN.m c) 14.6 kN.m d) - 272.1 kN.m e) 174.1 kN.m f) - 315.3 kN.m 4] What is the resultant moment of the five forces acting on the rod about point D? a) - 117.8 kN.m b) 82.7 kN.m c) 121.9 kN.m d) - 259.9 kN.m e) 127.1 kN.m f) 300.1 kN.m Activate 5] What is the moment of the force F2 about point E? a) 151.7 kN.m b) 118.1 kN.m c) 214.6 kN.m d) 158.6 kN.m e) 101.1 kN.m lo