Calculate the Moment About the Point A -20"- 5 lb 40 N D 1.5 m 40 N 4.5 m A 15 lb. 150 mm 52 N 5 12 100 mm 15 lb. 26 lb. 12 5 34 lb. 13 8 15 77777 36 lb.
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- The following diagram corresponds to questions 1 to 3. A beam rests on two sharp edges as shown on the image. The beam has a length of 7,50 m and a mass of 4,25 kg. Object 1 has a mass of 1,50 kg; object 2 has a mass of 2,35 kg. Point P is 0,50 m form the center of the beam. CG 1. How much is the torque done by object 1 around point P? A. 55,2 N*m B. 7,36 N*m C. 62,5 N*m D. Object 1 doesn't exert a torque. 2. How much is the torque done by the force of gravity of the beam around point P? A. 20,8 N*m N-m ך177 .B C. 156 N*m D. 313 N*m 3. If you needed to cancel the nomal forces of the two objects, where you should place object 2? The axis of rotation is point P. A. 3,30 m from point B. 9,18 m from point P C. 5,69 m from point P D. 3,62 m from point PPlease give the correct handwritten solution. Don't copy from othersites. Solution must be handwritten onlyI got these values for the moment about point B and I'm pretty sure the first two values are correct but I have no idea where I went wrong for force 3 if you could show how I could find the correct value of force 3's moment that would be really helpful
- Help!! Don’t copy last posted questionFL y b C Z Determine the moment about O due to the force F shown, the magnitude of the force F = 76.0 lbs. Note: Pay attention to the axis. Values for dimensions on the figure are given in the following table. Note the figure may not be to scale. Variable Value a 1.90 ft b 2.80 ft с 2.60 ft d 2.30 ft Mo 144 ft-lb = -212 × 1 + xk) ☑+212Express the 40 lb force in the rope from point A to point C in cartesian format. Point C is in the x-y plane and at an angle of 20 degrees from the y axis as shown. 4 ft 20 lb A B 3 ft X 40 lb Z 2 ft 1.5 ft 4.87i+27.6j - 28.5k lb -4.87i+27.6j + 28.5k lb -4.87i+27.6j - 28.5k lb 4.87i+22.8j - 32.5k lb 2 ft 20 y C
- 2/48 Calculate the moment MA of the 200-N force about point A by using three scalar methods and one vec- tor method. 200 N 7-A/1Y 15° B 280 mm A 400 mmF y b C 10 Z Determine the moment about O due to the force F shown, the magnitude of the force F = 76.0 lbs. Note: Pay attention to the axis. Values for dimensions on the figure are given in the following table. Note the figure may not be to scale. Variable Value a 1.90 ft b 2.80 ft с 2.60 ft d 2.30 ft Mo = lb + k) ft-Add the following forces to find the resultant force. V1 = 150 g @ 470 V2 = 550 @ 324° V3 = 350 g @ 215° V4 = 250 @ 172° V5 = 450 g @ 285°
- For multiple choice, choose the best answer. Show all work: indicate your plan and draw FBD's (Free Body Diagrams), write/label (symbolic) equations (e.g., ZFx = 0) before writing numeric equations, box answers. 1. What is the moment of the 12 N force about point A (MA)? 3 N-m 36 N-m a. b. C. 12/3 N-m d. 7 N-m F = 12 N d = 3 m3m Find the rectangular representation of the force F, given that its magnitude 240 N. * F = -135.76 i+ 169.71 j– 101.82 k F = 135.76 i + 169.71 j+ 101.82 k F = 135.76 i - 169.71 j+ 101.82 k F = -135.76i+ 169.71 j+ 101.82 kF1 F2 ba C F3 A B d. b F4 Consider the following values: - F5 a = 7 m; b = 3 m; c = 7 m; d = 3 m; F1 = 3 kN; F2 = 11 kN; F3 = 2 kN; F4 = 20 kN; F5 = 2 kN; a = 30° e = 60° , B = 30° 1] What is the resultant moment of the five forces acting on the rod about point A? a) 90.8 kN.m b) 72.7 kN.m c) 14.6 kN.m d) 55.9 kN.m e) 21.6 kN.m f) 61.3 kN.m 2] What is the resultant moment of the five forces acting on the rod about point B? a) 77.8 kN.m b) 25.7 kN.m c) 38.6 kN.m d) 18.9 kN.m e) 37.9 kN.m f) 84.2 kN.m 3] What is the resultant moment of the five forces acting on the rod about point C? a) 35.7 kN.m b) 21.1 kN.m c) 714.6 kN.m d) 69.1 kN.m e) 51.4 kN.m f) 85.3 kN.m 4] What is the resultant moment of the five forces acting on the rod about point D? a) 17.8 kN.m b) 55.7 kN.m c) 44.6 kN.m d) 18.9 kN.m e) 21.5 kN.m f) 30.1 kN.m 5] What is the moment of the force F2 about point E? a) 81.7 kN.m b) 78.1 kN.m c) 64.6 kN.m d) 73.1 kN.m e) 54.6 kN.m f) 61.3 kN.m