Calculate the molecules of oxygen required to react with 38.8 g of sulfur in the reaction below.25(6) + 302(g)→ 2SO3(g)O a. 1.09 x 1024 molecules oxygenOb.2.19 x 1024OC.4.86 x 1023 molecules oxygenO d.7.29 x 1025 molecules oxygenO e. 3.64 x 1023 molecules oxygenmolecules oxygen

Given, Amount of sulfur = 38.8 g Formula Used, Moles(n)=Given MassMolar Mass 1 mol has 6.023 x 1023…

Calculate the molecules of oxygen required to react with 38.8 g of sulfur in the reaction below. 2S(6) + 302(g) → 2S03() O a. 1.09 x 10-4 molecules oxygen Ob.2.19 x 1024 molecules oxygen OC.4.86 x 1023 molecules oxygen Od.7.29 x 1025 molecules oxygen Oe. 3.64 x 1025 molecules oxygen

Calculate the molecules of oxygen required to react with 38.8 g of sulfur in the reaction below. 2S(6) + 302(g) → 2S03() O a. 1.09 x 10-4 molecules oxygen Ob.2.19 x 1024 molecules oxygen OC.4.86 x 1023 molecules oxygen Od.7.29 x 1025 molecules oxygen Oe. 3.64 x 1025 molecules oxygen

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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Concept explainers

Stoichiometry

Stoichiometry is a chemical division that evaluates the quantitative content of the chemical process with the help of the reacting molecules or products taking part in the reaction. The term “stoicheion” in “Stoichiometry”, is an old Greek term for "element" whereas “metron” means "measure".

Question

Calculate the molecules of oxygen required to react with 38.8 g of sulfur in the reaction below.
25(6) + 302(g)→ 2SO3(g)
O a. 1.09 x 1024 molecules oxygen
Ob.2.19 x 1024
OC.4.86 x 1023 molecules oxygen
O d.7.29 x 1025 molecules oxygen
O e. 3.64 x 1023 molecules oxygen
molecules oxygen

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