-Calculate the molarity of the acetic acid solution in Figure 16B.1 if 25.0mL of that solution has been titrated with the 0.101 M solution of NaOH-Estimate the mass of KHP that will require 25 mL of 0.10 M NaOH toreach the equivalence point in a titration. Give the chemical equation for the reaction. FIGURE 16B.1An acid-base titration12curve resulting fromthe titration of asolution of acetic acid10Equivalence pointwith a 0.101 M solu-tion of NaOH. Theequivalence pointoccurs after the addi-tion of 27.02 mL ofthe NAOH solution.pH = pKa= 4.774I 27.02/2 = |13.51 mL27.02 mL1020304050Volume of NaOH added (mL)

a) Given :- Figure 16B.1 Volume of Acetic acid, CH3COOH = 25.0 mL = 0.025 L Molarity of NaOH =…

Answered: Calculate the molarity of the acetic…

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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-Calculate the molarity of the acetic acid solution in Figure 16B.1 if 25.0 mL of that solution has been titrated with the 0.101 M solution of NaOH -Estimate the mass of KHP that will require 25 mL of 0.10 M NaOH to reach the equivalence point in a titration. Give the chemical equation for the reaction.

FIGURE 16B.1
An acid-base titration
12
curve resulting from
the titration of a
solution of acetic acid
10
Equivalence point
with a 0.101 M solu-
tion of NaOH. The
equivalence point
occurs after the addi-
tion of 27.02 mL of
the NAOH solution.
pH = pKa
= 4.77
4
I 27.02/2 = |
13.51 mL
27.02 mL
10
20
30
40
50
Volume of NaOH added (mL)

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