An analytical chemist is titrating 64.9 mL of a 0.5800M solution of isopropylamine ((CH, CHNH, with a 0.3400M solution of HNO3. The p K, of isopropylamine is 3.33. Calculate the pH of the base solution after the chemist has added 69.8 mL of the HNO, solution to it. Note for advanced students: you may assume the final volume equals the initial volume of the solution plus the volume of HNO, solution added. Round your answer to 2 decimal places. pH =

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Chapter16: Acid-base Equilibria
Section: Chapter Questions
Problem 16.141QP: Ka for formic acid is 1.7 104 at 25C. A buffer is made by mixing 529 mL of 0.465 M formic acid,...
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An analytical chemist is titrating 64.9 mL of a 0.5800M solution of isopropylamine ((CH3),CHNH2)
with a 0.3400M solution of HNO3. The p K, of
isopropylamine is 3.33. Calculate the pH of the base solution after the chemist has added 69.8 mL of the HNO, solution to it.
Note for advanced students: you may assume the final volume equals the initial volume of the solution plus the volume of HNO,3 solution added.
Round your answer to 2 decimal places.
pH =
Transcribed Image Text:An analytical chemist is titrating 64.9 mL of a 0.5800M solution of isopropylamine ((CH3),CHNH2) with a 0.3400M solution of HNO3. The p K, of isopropylamine is 3.33. Calculate the pH of the base solution after the chemist has added 69.8 mL of the HNO, solution to it. Note for advanced students: you may assume the final volume equals the initial volume of the solution plus the volume of HNO,3 solution added. Round your answer to 2 decimal places. pH =
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