Calculate the masses of oxygen and nitrogen that are dissolved in 1.5 L of aqueous solution in equilibrium with air at 25 °C and 760 Torr. Assume that air is 21% oxygen and 78% nitrogen by volume. Henry's law constants for gases in water at 25 °C Gas TT. kh (bar - M-¹) 27 x 103

Chemistry: Principles and Reactions
8th Edition
ISBN:9781305079373
Author:William L. Masterton, Cecile N. Hurley
Publisher:William L. Masterton, Cecile N. Hurley
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1,324
A
Calculate the masses of oxygen and nitrogen that are
dissolved in 1.5 L of aqueous solution in equilibrium with air
at 25 °C and 760 Torr. Assume that air is 21% oxygen and
78% nitrogen by volume.
mass:
FEB
22
~
tv
mg 0₂
MacBook Pro
Henry's law constants for gases in water at
25 °C
mass:
Gas
He
N₂
0₂
CO2
H₂S
A O
kh (bar - M-¹)
2.7 x 10³
1.6 × 10³
7.9 x 10²
29
10.
W
mg
Transcribed Image Text:1,324 A Calculate the masses of oxygen and nitrogen that are dissolved in 1.5 L of aqueous solution in equilibrium with air at 25 °C and 760 Torr. Assume that air is 21% oxygen and 78% nitrogen by volume. mass: FEB 22 ~ tv mg 0₂ MacBook Pro Henry's law constants for gases in water at 25 °C mass: Gas He N₂ 0₂ CO2 H₂S A O kh (bar - M-¹) 2.7 x 10³ 1.6 × 10³ 7.9 x 10² 29 10. W mg
Expert Solution
Step 1

To solve this problem, we will use Henry's law, which relates the partial pressure of a gas above a liquid to the concentration of the gas dissolved in the liquid. The equation is:

P_gas = k_h * [gas]

where P_gas is the partial pressure of the gas above the liquid, [gas] is the concentration of the gas dissolved in the liquid, and k_h is the Henry's law constant for the gas at a given temperature.

 

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