Calculate the lattice enthalpy of MgBr2 given the following data below: Enthalpy of sublimation of Mg = +148 kJ/mol lonization enthalpy of Mg to Mg²* = +2187 kJ/mol Enthalpy of vaporization of Br2(1) = + 31 kJ/mol Enthalpy of dissociation of Br2(g) = +193 kJ/mol Enthalpy of electron affinity of Br(g) = 331 kJ/mol Enthalpy of formation of MgBr2(s) from Mg(s) and Br2(1) = -524 kJ/mol O a. 2197 kJ/mol O b. 3745 kJ/mol C. 2421 kJ/mol O d. 2390 kJ/mol O e. 2752 kJ/mol

Calculate the lattice enthalpy of MgBr2 given the following data below: Enthalpy of sublimation of Mg = +148 kJ/mol lonization enthalpy of Mg to Mg²* = +2187 kJ/mol Enthalpy of vaporization of Br2(1) = + 31 kJ/mol Enthalpy of dissociation of Br2(g) = +193 kJ/mol Enthalpy of electron affinity of Br(g) = 331 kJ/mol Enthalpy of formation of MgBr2(s) from Mg(s) and Br2(1) = -524 kJ/mol O a. 2197 kJ/mol O b. 3745 kJ/mol C. 2421 kJ/mol O d. 2390 kJ/mol O e. 2752 kJ/mol

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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