5) From the relative charges on the ions, we predict that the ion-ion attractions in CaF2 are greater than in NaF. Confirm this prediction by calculating the lattice energies of (a) NaF and (b) CaF2, given the following information: AHsub Na(s) = +109 kJ/mol and AHsub Ca(s) = +154 kJ/mol AHBE F2(g) +154 kJ/mol and AHIE1 Ca(g) = +590 kJ/mol AHEA F(g) -328 kJ/mol and AHIE2 Cal(g) = +1145 kJ/mol AHIE1 Na(g) = +495 kJ/mol

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Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
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Chapter1: Chemical Foundations
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Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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5) From the relative charges on the ions, we predict that the ion-ion attractions in CaF2
are greater than in NaF. Confirm this prediction by calculating the lattice energies of
(a) NaF and (b) CaF2, given the following information:
AHsub Na(s) = +109 kJ/mol and AHSub Ca(s) = +154 kJ/mol
AHBE F2(g) +154 kJ/mol and AHIE1 Ca(g) = +590 kJ/mol
AHEA F(g) = -328 kJ/mol and AHIE2 Cal(g) = +1145 kJ/mol
AHIE1 Na(g) = +495 kJ/mol
-
Transcribed Image Text:5) From the relative charges on the ions, we predict that the ion-ion attractions in CaF2 are greater than in NaF. Confirm this prediction by calculating the lattice energies of (a) NaF and (b) CaF2, given the following information: AHsub Na(s) = +109 kJ/mol and AHSub Ca(s) = +154 kJ/mol AHBE F2(g) +154 kJ/mol and AHIE1 Ca(g) = +590 kJ/mol AHEA F(g) = -328 kJ/mol and AHIE2 Cal(g) = +1145 kJ/mol AHIE1 Na(g) = +495 kJ/mol -
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