Please Answer Fast:Calculate the initial concentration of F e^ 3+ and SCN^ - , accounting for dilution using C1V1 = C2V2 for each solution in Table 2. Show an example calculation for solution A for both the iron(III) and thiocyanate ions. Enter all calculated values into Table 3. Soln.ABCDETable 3: Calculations for Determina3+Initial [Fe³+] M(accounting fordilution)Initial [SCN] M(accounting fordilution) Soln.ABCDEmL of Fe³+(2.00×10-³ M)CIV₁3.003.003.003.003.00Table 2: Analysis of Solutions Used to Determine KcmL of SCN-Absorbance Valuesat 447 nm(4.00×10-3 M)VimoveEI1.002.003.004.005.00AverageAbsorb.0.092 0.159 0.2020.149 0.082o. 159 0.1670.185 0.294 0.375 0.278 0.1850.292 0.285*0.498 0.4200.54€ 0.420 +498 0.416 0.4580.844 0.5380.6820.528 0.344-0.6020.539*0.4180.684 0.930 0.6426.48 0.718 0.649Note: All final volumes were 10.00 ml made up with 0. 500 M HNO3.

Here we would use dilution law , C1V1 = C2V2

Answered: Calculate the initial concentration of…

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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Please Answer Fast: Calculate the initial concentration of F e^ 3+ and SCN^ - , accounting for dilution using C1V1 = C2V2 for each solution in Table 2. Show an example calculation for solution A for both the iron(III) and thiocyanate ions. Enter all calculated values into Table 3.

Soln.
A
B
C
D
E
Table 3: Calculations for Determina
3+
Initial [Fe³+] M
(accounting for
dilution)
Initial [SCN] M
(accounting for
dilution)

Soln.
A
B
C
D
E
mL of Fe³+
(2.00×10-³ M)
CI
V₁
3.00
3.00
3.00
3.00
3.00
Table 2: Analysis of Solutions Used to Determine Kc
mL of SCN-
Absorbance Values
at 447 nm
(4.00×10-3 M)
Vi
move
EI
1.00
2.00
3.00
4.00
5.00
Average
Absorb.
0.092 0.159 0.2020.149 0.082o. 159 0.167
0.185 0.294 0.375 0.278 0.1850.292 0.285
*
0.498 0.4200.54€ 0.420 +498 0.416 0.458
0.844 0.5380.6820.528 0.344-0.6020.539
*
0.4180.684 0.930 0.6426.48 0.718 0.649
Note: All final volumes were 10.00 ml made up with 0. 500 M HNO3.

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