Calculate the heat released (kJ) in the reaction of 3.50 g of acetylene (C2H2) and excess hydrogen gas to form ethane gas: C2H2(g) + 2H2(g) C2H6(g) Given: 2C2H2(g) + 502g) 4CO2(g) + 2H20(g) AH = -2320 kJ/mol 2C2H6(g) + 702(g)→4CO2(g) + 6H20(g) AH = -3040 kJ/mol 2H2(g) + O2(g) 2H20(g) AH = -572 kJ/mol Multiple Choice None of the above 30.5 kJ 29.5 kJ 28.5 kJ 27.5 kJ

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Calculate the heat released (kJ) in the reaction of 3.50 g of acetylene (C2H2) and excess hydrogen gas to form ethane gas:
C2H2(g) + 2H2(g) → C2H6(g)
Given:
2C2H2(g) + 502(g) → 4CO2(g) + 2H20(g) AH = -2320 kJ/mol
2C2H6(g) + 702(g)→4CO2(g) + 6H20(g) AH = -3040 kJ/mol
2H2(g) + O2(g) 2H20(g) AH = -572 kJ/mol
Multiple Choice
None of the above
30.5 kJ
29.5 kJ
28.5 kJ
27.5 kJ
Transcribed Image Text:Calculate the heat released (kJ) in the reaction of 3.50 g of acetylene (C2H2) and excess hydrogen gas to form ethane gas: C2H2(g) + 2H2(g) → C2H6(g) Given: 2C2H2(g) + 502(g) → 4CO2(g) + 2H20(g) AH = -2320 kJ/mol 2C2H6(g) + 702(g)→4CO2(g) + 6H20(g) AH = -3040 kJ/mol 2H2(g) + O2(g) 2H20(g) AH = -572 kJ/mol Multiple Choice None of the above 30.5 kJ 29.5 kJ 28.5 kJ 27.5 kJ
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