Calculate the [H*] and [OH] in a solution prepared by diluting 0.10 mole of HCN and 0.10 mole of NaCN to 1 liter of water. KHCN = 7.2 x 10-10 [CN"] pH = pKa + log HCN) 0.10 mol/L = 9.14 + log o.10 moi/L 9.14

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1. Calculate the [H*] and [OH] in a solution prepared by diluting 0.10 mole of HCN and 0.10
mole of NaCN to 1 liter of water. KHCN = 7.2 x 10-10
pH = pKa + log
[CN ]
[HCN])
9.14 + log
0.10 mol/L
0.10 moi/L
9.14
Transcribed Image Text:1. Calculate the [H*] and [OH] in a solution prepared by diluting 0.10 mole of HCN and 0.10 mole of NaCN to 1 liter of water. KHCN = 7.2 x 10-10 pH = pKa + log [CN ] [HCN]) 9.14 + log 0.10 mol/L 0.10 moi/L 9.14
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