Calculate the Gibbs free energy (in kJ/mol) at 25 degrees C of the following reaction using the data in the table. 4A +5B → 5C + 1D + 5E AHfo(kJ/mol) A -35.72 B-59.40 C -1.94 D -13.58 E 51.57 Answer: so(J/mol/K) 183.16 141.41 32.74 88.31 82.41 231,812.19 x (905.59) J/molx (kJ/mol)
Calculate the Gibbs free energy (in kJ/mol) at 25 degrees C of the following reaction using the data in the table. 4A +5B → 5C + 1D + 5E AHfo(kJ/mol) A -35.72 B-59.40 C -1.94 D -13.58 E 51.57 Answer: so(J/mol/K) 183.16 141.41 32.74 88.31 82.41 231,812.19 x (905.59) J/molx (kJ/mol)
Chemistry: Principles and Practice
3rd Edition
ISBN:9780534420123
Author:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward Mercer
Publisher:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward Mercer
Chapter17: Chemcial Thermodynamics
Section: Chapter Questions
Problem 17.107QE: Calculate the standard Gibbs free-energy change when SO3 forms from SO2 and O2 at 298 K. Why is...
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![Calculate the Gibbs free energy (in kJ/mol) at 25 degrees C of the following reaction using the data in the
table.
4A +5B 5C + 1D + 5E
AHfo(kJ/mol)
A -35.72
B
-59.40
C -1.94
D -13.58
E 51.57
Answer:
so(J/mol/K)
183.16
141.41
32.74
88.31
82.41
231,812.19 x (905.59) J/mol x (kJ/mol)](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F6ae95cc5-a0cd-43b0-8331-9678c9dacca0%2F013cc5b2-4b77-48da-86e9-40066cbcafcf%2Fx0dawq_processed.png&w=3840&q=75)
Transcribed Image Text:Calculate the Gibbs free energy (in kJ/mol) at 25 degrees C of the following reaction using the data in the
table.
4A +5B 5C + 1D + 5E
AHfo(kJ/mol)
A -35.72
B
-59.40
C -1.94
D -13.58
E 51.57
Answer:
so(J/mol/K)
183.16
141.41
32.74
88.31
82.41
231,812.19 x (905.59) J/mol x (kJ/mol)
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