Calculate the enthalpy change of the following reaction, given equations (1), (2) and (3). Ca(OH)2(aq) + 2HCI(aq) CaCl2(aq) + 2H20(6) --> (1) CaO(s) + 2HCI(aq) CaCl2(aq) + H2O(); AH° = --> -186 kJ (2) CaO(s) + H20(E) --> Ca(OH)2(s); AH° = -62.3 kJ AH° = -12.6 Ca(OH)2(aq) H2O (3) Ca(OH)2(s) --> kJ

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Pls help ASAP. PLS look at the diagram of the graph to answer this. 

Calculate the enthalpy change of the following reaction, given equations (1), (2) and
(3).
Ca(OH)2(aq) + 2HCI(aq)
CaCl2(aq) + 2H20(6)
-->
(1)
CaO(s) + 2HCI(aq)
CaCl2(aq) + H2O();
AH° =
-->
-186 kJ
(2)
CaO(s) +
H20(E) --> Ca(OH)2(s);
AH° = -62.3
kJ
Ca(OH)2(s)
AH° = -12.6
Ca(OH)2(aq)
H2O
(3)
-->
kJ
Transcribed Image Text:Calculate the enthalpy change of the following reaction, given equations (1), (2) and (3). Ca(OH)2(aq) + 2HCI(aq) CaCl2(aq) + 2H20(6) --> (1) CaO(s) + 2HCI(aq) CaCl2(aq) + H2O(); AH° = --> -186 kJ (2) CaO(s) + H20(E) --> Ca(OH)2(s); AH° = -62.3 kJ Ca(OH)2(s) AH° = -12.6 Ca(OH)2(aq) H2O (3) --> kJ
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