Calculate the energy required to heat 1.80 kg of ammonia from 21.5 °C to 41.0 °C. Assume the specific heat capacity of 1 1 ammonia under these conditions is 4.70 J-g''K. Round your answer to 3 significant digits.
Calculate the energy required to heat 1.80 kg of ammonia from 21.5 °C to 41.0 °C. Assume the specific heat capacity of 1 1 ammonia under these conditions is 4.70 J-g''K. Round your answer to 3 significant digits.
Chemistry
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ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
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Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Question
Calculate the energy required to heat 1.80kg of ammonia from 21.5°C to 41.0°C . Assume the specific heat capacity of ammonia under these conditions is ·4.70J·g−1K−1 Round your answer to 3 significant digits.
![**Problem Statement:**
Calculate the energy required to heat 1.80 kg of ammonia from 21.5 °C to 41.0 °C. Assume the specific heat capacity of ammonia under these conditions is \( 4.70 \, \text{J} \cdot \text{g}^{-1} \cdot \text{K}^{-1} \). Round your answer to 3 significant digits.
**Explanation:**
To solve this problem, you would apply the formula for calculating energy required for heating:
\[
q = m \cdot c \cdot \Delta T
\]
where:
- \( q \) is the heat energy (in joules),
- \( m \) is the mass of the substance (in grams),
- \( c \) is the specific heat capacity (in \(\text{J} \cdot \text{g}^{-1} \cdot \text{K}^{-1}\)),
- \( \Delta T \) is the change in temperature (in Kelvin or Celsius since the scale increment is the same for both).
Note: Temperature change \( \Delta T = \text{final temperature} - \text{initial temperature} = 41.0°C - 21.5°C = 19.5°C \).
Make sure to convert the mass from kilograms to grams (1.80 kg = 1800 g) before applying the formula.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F1e77a53e-015e-4d74-8706-0af5e82649c9%2Fd0f60be1-8d59-4eee-92c3-f5db400f9d06%2Fuf2wrlq_processed.png&w=3840&q=75)
Transcribed Image Text:**Problem Statement:**
Calculate the energy required to heat 1.80 kg of ammonia from 21.5 °C to 41.0 °C. Assume the specific heat capacity of ammonia under these conditions is \( 4.70 \, \text{J} \cdot \text{g}^{-1} \cdot \text{K}^{-1} \). Round your answer to 3 significant digits.
**Explanation:**
To solve this problem, you would apply the formula for calculating energy required for heating:
\[
q = m \cdot c \cdot \Delta T
\]
where:
- \( q \) is the heat energy (in joules),
- \( m \) is the mass of the substance (in grams),
- \( c \) is the specific heat capacity (in \(\text{J} \cdot \text{g}^{-1} \cdot \text{K}^{-1}\)),
- \( \Delta T \) is the change in temperature (in Kelvin or Celsius since the scale increment is the same for both).
Note: Temperature change \( \Delta T = \text{final temperature} - \text{initial temperature} = 41.0°C - 21.5°C = 19.5°C \).
Make sure to convert the mass from kilograms to grams (1.80 kg = 1800 g) before applying the formula.
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