5 Calculate the electrode potential of the system at the equivalence point for each of the following reactions. Use 0.100 M where a value for [H+] isneeded and is not otherwise specified.а. Fe3++ Cr²+Fe?+ + Cr3+(E= 0.771 V, E= -0.408 V)Fe+* /Fe²+Cr3+ /Cr2+Potential =Vb. Fe (CN)63-+ Cr+ = Fe (CN),4-+ Cr3+e (CN)," /Pe (CN),"= 0.360 V, E+ /Cr?+= -0.408 V)4-FePotential =Vc. TIš+ + 2C02+ TIt + 2C03+(E.(T1³+ /TI+—D 1.25 V, ЕОCo3+/Co2+= 1.808 V)Potential =V

Answered: Image /qna-images/answer/8783220a-6914-4172-bc4e-5ac24336a1ed.jpg

Calculate the electrode potential of the system at the equivalence point for each of the following reactions. Use 0.100 M where a value for [H* needed and is not otherwise specified. is a. Fe+ + Cr3+ Fe2+ + Cr³+ (E. */Fe?+ = 0.771 V, Es+ Cr+ /Cr²+ = -0.408 V) Potential = V 3- 4- b. Fe (CN), + Cr²+ = Fe (CN),“ + Cr³+ (E Fe (CN),"/Fe (CN),“ = 0.360 V, E* /C?²+ - 0.408 V) Potential = V c. TI3+ + 2C0²+ TI* + 2C0³+ (E TIs+ /TI* = 1.25 V, E+ /C2+ = 1.808 V)

Calculate the electrode potential of the system at the equivalence point for each of the following reactions. Use 0.100 M where a value for [H* needed and is not otherwise specified. is a. Fe+ + Cr3+ Fe2+ + Cr³+ (E. /Fe?+ = 0.771 V, Es+ Cr+ /Cr²+ = -0.408 V) Potential = V 3- 4- b. Fe (CN), + Cr²+ = Fe (CN),“ + Cr³+ (E Fe (CN),"/Fe (CN),“ = 0.360 V, E /C?²+ - 0.408 V) Potential = V c. TI3+ + 2C0²+ TI* + 2C0³+ (E TIs+ /TI* = 1.25 V, E+ /C2+ = 1.808 V)

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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Concept explainers

Potentiometric Titrations

Potentiometric titration is one of the important titration methods and is mainly carried out to characterize acid solutions. It follows a method similar to that of the normal titration technique, but the main difference is that there is no indicator used in the potentiometric titrations. Instead of using an indicator, electrodes are employed for monitoring the whole titration process. A scientist named Robert Behrend did the potentiometric titration for the first time, and it was done using the mercurous solution and potassium chloride.

Question

Calculate the electrode potential of the system at the equivalence point for each of the following reactions. Use 0.100 M where a value for [H+] is
needed and is not otherwise specified.
а. Fe3+
+ Cr²+
Fe?+ + Cr3+
(E
= 0.771 V, E
= -0.408 V)
Fe+
* /Fe²+
Cr3+ /Cr2+
Potential =
V
b. Fe (CN)6
3-
+ Cr+ = Fe (CN),
4-
+ Cr3+
e (CN)," /Pe (CN),"
= 0.360 V, E+ /Cr?+
= -0.408 V)
4-
Fe
Potential =
V
c. TIš+ + 2C02+ TIt + 2C03+
(E.
(T1³+ /TI+
—D 1.25 V, ЕО
Co3+
/Co2+
= 1.808 V)
Potential =
V

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