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Calculate the concentration of an HCI solution if 100.0 mL of the HCI required 33.00 mL of 0.2000 M Mg(OH)₂ to reach the titration endpoint. Mg(OH)₂ + 2 HCI 2 H₂O + MgCl₂ There is enough information to calculate the moles of base but not the moles of acid. mol ( L)(- mol Mg(OH)3 mol HCI ( mol Mg(OH)3)(- mol HCI mol Mg(OH)2 mol HCI L a. 0.1000 h. CaCO3(s) 0. H₂PO4¹ v. H₂CO3 bb. 3.300 x 10-² hh. 2.16 x 10-6 b. 0.1320 i. OH-¹ p. CO3-² W. PO43 C. HX j. H30+1 q. HCO3-1 x. HC₂H302 dd. 2 cc. 3 ii. 1.60 x 10-5 = d. Al+3 K. SO4² r. H₂S jj. 0.2000 L e. CO₂ y. C₂H30₂-1 ee. 1 I. Mg+2 S. HS-1 -) = M HCI f. CaF2(aq) m. Cl-1 t. S-2 z. 1 x 10-14 ff. 0.099536 kk. 6.600 x 10-3 -) = g. HF (aq) n. HPO4² u. H₂O(liq) aa. 1.32 x 10-² gg. 3.95 x 10-3

Calculate the concentration of an HCI solution if 100.0 mL of the HCI required 33.00 mL of 0.2000 M Mg(OH)₂ to reach the titration endpoint. Mg(OH)₂ + 2 HCI 2 H₂O + MgCl₂ There is enough information to calculate the moles of base but not the moles of acid. mol ( L)(- mol Mg(OH)3 mol HCI ( mol Mg(OH)3)(- mol HCI mol Mg(OH)2 mol HCI L a. 0.1000 h. CaCO3(s) 0. H₂PO4¹ v. H₂CO3 bb. 3.300 x 10-² hh. 2.16 x 10-6 b. 0.1320 i. OH-¹ p. CO3-² W. PO43 C. HX j. H30+1 q. HCO3-1 x. HC₂H302 dd. 2 cc. 3 ii. 1.60 x 10-5 = d. Al+3 K. SO4² r. H₂S jj. 0.2000 L e. CO₂ y. C₂H30₂-1 ee. 1 I. Mg+2 S. HS-1 -) = M HCI f. CaF2(aq) m. Cl-1 t. S-2 z. 1 x 10-14 ff. 0.099536 kk. 6.600 x 10-3 -) = g. HF (aq) n. HPO4² u. H₂O(liq) aa. 1.32 x 10-² gg. 3.95 x 10-3

Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Calculate the concentration of an HCI solution if 100.0 mL of the HCI required 33.00 mL of 0.2000 M Mg(OH)₂ to reach the titration endpoint. Mg(OH)₂ + 2 HCI 2 H₂O + MgCl₂ There is enough information to calculate the moles of base but not the moles of acid. mol L)(-- mol Mg(OH)3 mol HCI ( mol Mg(OH)3)(-- mol HCI mol Mg(OH)2 mol HCI a. 0.1000 b. 0.1320 c. HX d. Al+3 h. CaCO3(s) i. OH-1 j. H30+1 k. SO4² -1 -2 0. H₂PO4-¹ p. CO3-² v. H₂CO3 W. PO4-³ bb. 3.300 x 10-² q. HCO3-1 r. H₂S x. HC₂H302 y. C₂H30₂-1 dd. 2 ee. 1 jj. 0.2000 hh. 2.16 x 10-6 CC. 3 ii. 1.60 x 10-5 L e. CO₂ -) = M HCI f. CaF2(aq) m. Cl-1 t. S-² 1 x 10-14 I. Mg+2 s. HS-1 ff. 0.099536 kk. 6.600 x 10-³ -) = g. HF (aq) n. HPO4² u. H₂O(liq) aa. 1.32 x 10-² gg. 3.95 x 10-3
Transcribed Image Text:Calculate the concentration of an HCI solution if 100.0 mL of the HCI required 33.00 mL of 0.2000 M Mg(OH)₂ to reach the titration endpoint. Mg(OH)₂ + 2 HCI 2 H₂O + MgCl₂ There is enough information to calculate the moles of base but not the moles of acid. mol L)(-- mol Mg(OH)3 mol HCI ( mol Mg(OH)3)(-- mol HCI mol Mg(OH)2 mol HCI a. 0.1000 b. 0.1320 c. HX d. Al+3 h. CaCO3(s) i. OH-1 j. H30+1 k. SO4² -1 -2 0. H₂PO4-¹ p. CO3-² v. H₂CO3 W. PO4-³ bb. 3.300 x 10-² q. HCO3-1 r. H₂S x. HC₂H302 y. C₂H30₂-1 dd. 2 ee. 1 jj. 0.2000 hh. 2.16 x 10-6 CC. 3 ii. 1.60 x 10-5 L e. CO₂ -) = M HCI f. CaF2(aq) m. Cl-1 t. S-² 1 x 10-14 I. Mg+2 s. HS-1 ff. 0.099536 kk. 6.600 x 10-³ -) = g. HF (aq) n. HPO4² u. H₂O(liq) aa. 1.32 x 10-² gg. 3.95 x 10-3
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