At 25.00 °C, What is the pH of an aqueous 2.50 x 10-8 M HCl solution? The pH of ANY aqueous acid will NEVER be greater than 7.00, REGARDLESS of the acid's concentration! This is because of the "LEVELING EFFECT" of pure water, whose [H+] = 1.0 x 107 M. Thus, the TOTAL [H+] of the solution will be: 1.0 x 107 M +2.50 x 10-8 M = 1.25 x 107 M, thus the pH of the 2.5 x 10-8 M HCl solution will be 6.90 because the contribution of H+ from the autoionization of pure water is greater than that for the very dilute acid, and MUST be accounted for!!!. NOTE: If the acid is di- (or tri-) protic, you must also take that into account!!!
At 25.00 °C, What is the pH of an aqueous 2.50 x 10-8 M HCl solution? The pH of ANY aqueous acid will NEVER be greater than 7.00, REGARDLESS of the acid's concentration! This is because of the "LEVELING EFFECT" of pure water, whose [H+] = 1.0 x 107 M. Thus, the TOTAL [H+] of the solution will be: 1.0 x 107 M +2.50 x 10-8 M = 1.25 x 107 M, thus the pH of the 2.5 x 10-8 M HCl solution will be 6.90 because the contribution of H+ from the autoionization of pure water is greater than that for the very dilute acid, and MUST be accounted for!!!. NOTE: If the acid is di- (or tri-) protic, you must also take that into account!!!
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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How to calculate the ph? What would be the result if the acid was a di or tripotic? How do the calculation for them?
![At 25.00 °C, What is the pH of an aqueous 2.50 x 10-8 M HCl solution?
The pH of ANY aqueous acid will NEVER be greater than 7.00, REGARDLESS of the
acid's concentration! This is because of the "LEVELING EFFECT" of pure water, whose
[H+] = 1.0 x 107 M. Thus, the TOTAL [H+] of the solution will be: 1.0 x 107 M +2.50 x
10-8 M = 1.25 x 107 M, thus the pH of the 2.5 x 10-8 M HCl solution will be 6.90
because the contribution of H+ from the autoionization of pure water is greater than
that for the very dilute acid, and MUST be accounted for!!!.
NOTE: If the acid is di- (or tri-) protic, you must also take that into account!!!](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F637a8243-98d2-45ca-8dd1-4e9d7d0f97ca%2F7295c292-a294-4767-a64c-ec679da936f5%2Fsb0i80o.jpeg&w=3840&q=75)
Transcribed Image Text:At 25.00 °C, What is the pH of an aqueous 2.50 x 10-8 M HCl solution?
The pH of ANY aqueous acid will NEVER be greater than 7.00, REGARDLESS of the
acid's concentration! This is because of the "LEVELING EFFECT" of pure water, whose
[H+] = 1.0 x 107 M. Thus, the TOTAL [H+] of the solution will be: 1.0 x 107 M +2.50 x
10-8 M = 1.25 x 107 M, thus the pH of the 2.5 x 10-8 M HCl solution will be 6.90
because the contribution of H+ from the autoionization of pure water is greater than
that for the very dilute acid, and MUST be accounted for!!!.
NOTE: If the acid is di- (or tri-) protic, you must also take that into account!!!
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