Calculate the concentration of all species in a 0.215 M C6H5NH3C1 solution (Kh is 3.9 x 10-19. Enter your answers numerically separated by commas. Express your answer using two significant figures. ? (C¢H;NH†], [CI¯], [C¢H;NH2), [H3O†), [OH¯] = M

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I Review | ConstantsS | Periodic Table
MISSED THIS? Read Section 17.8 (Pages 758 - 765) ; Watch
KCV 17.8, IWE 17.14, 17.16.
Part A
Calculate the concentration of all species in a 0.215 M C6H5NH3C1 solution (Kb is 3.9 × 10-19.
Enter your answers numerically separated by commas. Express your answer using two significant figures.
?
[C¢H&NH}], [CI¯], [C¢H5NH2], [H3O*J, [OH¯] =
M
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Transcribed Image Text:I Review | ConstantsS | Periodic Table MISSED THIS? Read Section 17.8 (Pages 758 - 765) ; Watch KCV 17.8, IWE 17.14, 17.16. Part A Calculate the concentration of all species in a 0.215 M C6H5NH3C1 solution (Kb is 3.9 × 10-19. Enter your answers numerically separated by commas. Express your answer using two significant figures. ? [C¢H&NH}], [CI¯], [C¢H5NH2], [H3O*J, [OH¯] = M Submit Request Answer
Expert Solution
Step 1

Given:

Concentration of C6H5NH3Cl = 0.215 M

Kb of aniline = 3.9 x 10-10

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