Calculate the change in entropy if Br2() is converted to Br2(g).TJ/KSo for Br2()=152.2 J/(mol⚫K)So for Br2(g)=245.5 J/(mol⚫K)So for Br(g)=175.0 J/(mol K)Part 3 (1 point)Calculate the change in entropy if Br() is converted into gaseous Brators.J/KSo for Br₂(1)=152.2 J/(mol⚫K)So for Br2(g)=245.5 J/(mol⚫K)So for Br(g)=175.0 J/(mol⚫K)

To calculate change in entropy we use formula ∆S° = sum of entropy of products multiplying by its…

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Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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For the following reactions, indicate whether the entropy of the system increases, decreases, or remains nearly the same. ( Circle) a) Al3* (aq) + 3 OH" (aq) → Al(OH)3 (s) increase decrease remains nearly the same b) CaCO3(s) → CaO(s) + CO2(g) increase decrease remains nearly the same c) Mg(s) + Cu2+(aq) → Mg²*(aq) + Cu(s) increase decrease remains nearly the same Rank the compounds in each of the following groups in order of increasing standard molar entropy. a) CHa(g), CF4(g), CCI1(g) b) CH20(g), CH3CHO(g), CH3CH2CHO (g). c) HF(g), H20(g), NH3(g).
Here are some relevant excerpts from the tables of standard thermodynamic data: Substance ΔHfo(kJ/mol) H2O (l) -286 NO (g) 90 NO2 (g) 34 HNO3 (aq) -207 NH3 (g) -46 Find ΔHo in kJ of 4NH3(g) + 5 O2 (g) --> 4 NO (g) + 6 H2O (l) Question 15 options: -1540 kJ -1172 kJ -1892 kJ -150 kJ
In a reaction, 1.00 mole of H2 is produced at a constant pressure of 1.00 atm and at 298 K (1 L atm = 101.3 J): 2 H2O(g) → 2 H2(g) + O2(g) ΔH° = +483.6 kJ mol–1 How much heat is exchanged in this reaction? +483.6 kJ +967.2 kJ +241.8 kJ
Consider the reactionCa(OH)2(aq) + 2HCl(aq)CaCl2(s) + 2H2O(l)for which H° = -30.20 kJ and S° = 205.9 J/K at 298.15 K.(1) Calculate the entropy change of the UNIVERSE when 2.325 moles of Ca(OH)2(aq) react under standard conditions at 298.15 K.Suniverse = J/K(2) Is this reaction reactant or product favored under standard conditions?(3) If the reaction is product favored, is it enthalpy favored, entropy favored, or favored by both enthalpy and entropy? If the reaction is reactant favored, choose 'reactant favored'.
4.
Consider the reaction 2NaOH(aq) + H2(g)—2Na(s) + 2H2O(l) for which AH° = 368.6 kJ and AS° = 15.30 J/K at 298.15 K. (1) Calculate the entropy change of the UNIVERSE when 1.759 moles of NaOH(aq) react under standard conditions at 298.15 K. ASuniverse= J/K (2) Is this reaction reactant or product favored under standard conditions? (3) If the reaction is product favored, is it enthalpy favored, entropy favored, or favored by both enthalpy and entropy? If the reaction is reactant favored, choose 'reactant favored'. Submit Answer
What is the change in entropy, AS, for the following reaction? Use Table G in your book for values of standard entropies. Your answer should be in J/K mol. CaCO3(s) + 2 H'(aq) → → Ca² (aq) + H₂O(l) + CO2(g) O 264.9 J/K mol O 118.6 J/K mol 394.3 J/K mol 137.7 J/K mol 2
Mark the correct statements. (Select all that apply.) O [The reaction 2H20(g) → 2H2(g) + O2(g) is expected to have a positive value of ASº.] O [If a sample of pure ozone changed to oxygen at constant T and P, the entropy of the sample would decrease.] O [For the process H20(1) → H20(s) occurring at 0°C and 1 atm, the sign of AS is negative.] O [The value of AS for the process CHC13(1) – CHC13(g) is negative.] O [The reaction CH4(g) + 202(g) → CO2(g) + 2H2O(g) has a negative value of ASsurr-]
Consider the reaction Fe(s) + 2HCl(aq) → FeCl₂ (s) + H₂(g) for which AH = -7.400 kJ and AS = 107.9 J/K at 298.15 K. 1. Calculate the entropy change of the UNIVERSE when 2.385 moles of Fe(s) react under standard conditions at 298.15 K. ASuniverse J/K 2. Is this reaction reactant or product favored under standard conditions? 3. If the reaction is product favored, is it enthalpy favored, entropy favored, or favored by both enthalpy and entropy? If the reaction is reactant favored, choose 'reactant favored'. Submit Answer Retry Entire Group 5 more group attempts remaining
Given the values of So given below in J/mol K and of ΔHfo given in kJ/mol, calculate the value of ΔGo in kJ for the combustion of 1 mole of ethane to form carbon dioxide and gaseous water at 298 K. S (C2H6(g)) = 227 S (O2(g)) = 209 S (CO2(g)) = 219 S (H2O(g)) = 184 ΔHfo (C2H6(g)) = -86 ΔHfo (CO2(g)) = -398 ΔHfo (H2O(g)) = -244
(Q74) A certain process is nonspontaneous at low temperatures. Given that AHX = 201.2 kJ and ASPxn = 876 J/K, at what temperature (in °C) will the process become spontaneous? %3D (Report your Celsius temperature to one decimal place --> if your answer has a decimal place of "O" and Canvas chops it off, don't worry about it).
For the reactionNH4NO3(aq) N2O(g) + 2 H2O(l)G° = -175.3 kJ and H° = -149.6 kJ at 257 K and 1 atm.This reaction is (reactant, product) favored under standard conditions at 257 K.The entropy change for the reaction of 1.74 moles of NH4NO3(aq) at this temperature would be J/K.

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