Calculate the AS°rxn for the reaction 2NO,(g) → N204(g) at 530 K. [The standard molar heat capacities for each compound are: N,O4 (79.2 J/K · mol), NO2 (37.2 J/K · mol).] ЈK mol

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Calculate the AS°rxn for the reaction
2NO,(g) → N204(g)
at 530 K. [The standard molar heat capacities for each compound are: N,O4 (79.2 J/K · mol),
NO2 (37.2 J/K · mol).]
ЈK mol
Transcribed Image Text:Calculate the AS°rxn for the reaction 2NO,(g) → N204(g) at 530 K. [The standard molar heat capacities for each compound are: N,O4 (79.2 J/K · mol), NO2 (37.2 J/K · mol).] ЈK mol
Expert Solution
Step 1

given :

2NO2 (g) -----> N2O4 (g)

Temperature = 530 K

Molar heat capacity of N2O4 = 79.2 J/K .mol

molar heat capacity of  NO2 = 37.2  J/K.mol

standard entropy of N2O4 at 298K=304.29 J/K.mol 

standard entropy of NO2 at 298K = 240.06 J/K.mol

we have to find Delta S of a reaction ?

 

Step 2

delta S° = S°N2O4 - 2× S°NO2

              = 304.29 - 2× 240.06

             = -175.83 J/mol.K

Delta Cp = Cp N2O4 - 2 × Cp NO2

                =  79.2 - 2 × 37.2

               = 4.8 J/K.mol

 

 

 

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