3 If we measure the heat change (q) of everything in a system except the calorimeter, we can use the first law of thermodynamics (∆Euniverse = 0) to calculate the heat change of the calorimeter (qcal). In this reaction, we combine 5.75 g of 67.4 ºC water with 6.67 g of 19 ºC water in a calorimeter. Since some of the heat is absorbed by the calorimeter, the final temperature of the water is 25.4ºC. Since the hot and cold water are combined, the final temp of the water is the final temp for the hot water and the cold water. Calculate the heat change of the calorimeter in J. Remember that all of the heat changes must add up to zero so you can calculate the heat change of the hot water (qhotwater) and the heat change of the cold water (qcoldwater) using for each where Cs = 4.186 J/gºC. The first law of thermodynamics tells us that all of these changes sum up to zero so Enter your answer to one decimal place (tenths)
Thermochemistry
Thermochemistry can be considered as a branch of thermodynamics that deals with the connections between warmth, work, and various types of energy, formed because of different synthetic and actual cycles. Thermochemistry describes the energy changes that occur as a result of reactions or chemical changes in a substance.
Exergonic Reaction
The term exergonic is derived from the Greek word in which ‘ergon’ means work and exergonic means ‘work outside’. Exergonic reactions releases work energy. Exergonic reactions are different from exothermic reactions, the one that releases only heat energy during the course of the reaction. So, exothermic reaction is one type of exergonic reaction. Exergonic reaction releases work energy in different forms like heat, light or sound. For example, a glow stick releases light making that an exergonic reaction and not an exothermic reaction since no heat is released. Even endothermic reactions at very high temperature are exergonic.
3
If we measure the heat change (q) of everything in a system except the calorimeter, we can use the first law of
Remember that all of the heat changes must add up to zero so you can calculate the heat change of the hot water (qhotwater) and the heat change of the cold water (qcoldwater) using for each where Cs = 4.186 J/gºC. The first law of thermodynamics tells us that all of these changes sum up to zero so
Enter your answer to one decimal place (tenths)
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