Calculate the AH°, for the reaction below, in kJ, using the heat of formation values below: _X4Y2 (g) + _Z6 (g) → _X2Z4 (g) + Y4Z2 ) ---- AH°; [X4Y2 (g)] = -300.5 kJ/mol %3D AH°; [Z6 (3)] = 0 kJ/mol AH°f [X2Z4 (g)] = -110.4 kJ/mol AH°; [Y4Z2 ()] = 278.9 kj/mol HINT: Balance the reaction FIRST!
Calculate the AH°, for the reaction below, in kJ, using the heat of formation values below: _X4Y2 (g) + _Z6 (g) → _X2Z4 (g) + Y4Z2 ) ---- AH°; [X4Y2 (g)] = -300.5 kJ/mol %3D AH°; [Z6 (3)] = 0 kJ/mol AH°f [X2Z4 (g)] = -110.4 kJ/mol AH°; [Y4Z2 ()] = 278.9 kj/mol HINT: Balance the reaction FIRST!
Chemistry
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ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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![**Calculate the ΔH°_rxn for the reaction below, in kJ, using the heat of formation values:**
\[
\text{____X}_4\text{Y}_2 \text{(g) + ____Z}_6\text{ (g)} \rightarrow \text{____X}_2\text{Z}_4 \text{(g) + ____Y}_4\text{Z}_2 \text{(l)}
\]
- ΔH°_f [X₄Y₂ (g)] = -300.5 kJ/mol
- ΔH°_f [Z₆ (g)] = 0 kJ/mol
- ΔH°_f [X₂Z₄ (g)] = -110.4 kJ/mol
- ΔH°_f [Y₄Z₂ (l)] = 278.9 kJ/mol
**HINT:** Balance the reaction FIRST!](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fbf8e267e-10e5-42d7-8fd7-a8f3672a74ed%2Fcf5b8d64-f3ab-472f-a3c4-ad7e575ec16a%2Fpf8vu6e_processed.jpeg&w=3840&q=75)
Transcribed Image Text:**Calculate the ΔH°_rxn for the reaction below, in kJ, using the heat of formation values:**
\[
\text{____X}_4\text{Y}_2 \text{(g) + ____Z}_6\text{ (g)} \rightarrow \text{____X}_2\text{Z}_4 \text{(g) + ____Y}_4\text{Z}_2 \text{(l)}
\]
- ΔH°_f [X₄Y₂ (g)] = -300.5 kJ/mol
- ΔH°_f [Z₆ (g)] = 0 kJ/mol
- ΔH°_f [X₂Z₄ (g)] = -110.4 kJ/mol
- ΔH°_f [Y₄Z₂ (l)] = 278.9 kJ/mol
**HINT:** Balance the reaction FIRST!
Expert Solution

Step 1
Given
Reaction
X4Y2(g) + Z6(g) X2Z4(g) + Y4Z2(l)
∆H°f [ X4Y2 (g) ] = - 300.5 KJ/mol
∆H°f [ Z6(g) ] = 0 KJ/mol
∆H°f [ X2Z4 (g) ] = - 110.4 KJ/mol
∆H°f [ Y4Z2 ( l ) ] = 278.9 KJ/mol
∆H°( r×n ) = ?
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