Fast pls solve this question correctly in 5 min pls I will give u like for sure Nidi If you could answer both, I'd be grateful. I'll give a thumbs up, thanks. Only a brief explanation is needed. Calculate P(FIE), ifP(E|F) = 0.72P(E) = 0.9P(F) = 0.57Round your answer to five decimals.Answer: Muscular dystrophy is a genetic disease caused by a mutation on the X chromosome. During reproduction this mutation arises spontaneously on each of the Xchromosomes of the parents, independently and with probability μ = 0.884. We can therefore view the production of a child as consisting of two probabilisticexperiments. First, one of the two sex chromosomes is chosen with equal probability from each parent. Second, for each X chromosome that is chosen, themuscular dystrophy mutation arises independently with probability . All male children carrying the mutation will develop muscular dystrophy, whereas only femaleswhose X chromosomes both carry the mutation will develop the disease. What is the probability that a child will develop the disease? Round your answer to fivedecimal places.Answer:

Given that P(E/F)=0.72 , P(E)=0.9 and P(F)=0.57 We know that P(E/F)=P(E∩F)P(F)or, 0.72…

Answered: Calculate P(FIE), if P(E|F) = 0.72 P(E)…

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Calculate P(FIE), if P(E|F) = 0.72 P(E) = 0.9 P(F) = 0.57 Round your answer to five decimals. Answer:

Advanced Engineering Mathematics

10th Edition

ISBN:9780470458365

Author:Erwin Kreyszig

Publisher:Erwin Kreyszig

Chapter2: Second-order Linear Odes

Section: Chapter Questions

Problem 1RQ

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Question

Fast pls solve this question correctly in 5 min pls I will give u like for sure

Nidi

If you could answer both, I'd be grateful. I'll give a thumbs up, thanks. Only a brief explanation is needed.

Calculate P(FIE), if
P(E|F) = 0.72
P(E) = 0.9
P(F) = 0.57
Round your answer to five decimals.
Answer:

Muscular dystrophy is a genetic disease caused by a mutation on the X chromosome. During reproduction this mutation arises spontaneously on each of the X
chromosomes of the parents, independently and with probability μ = 0.884. We can therefore view the production of a child as consisting of two probabilistic
experiments. First, one of the two sex chromosomes is chosen with equal probability from each parent. Second, for each X chromosome that is chosen, the
muscular dystrophy mutation arises independently with probability . All male children carrying the mutation will develop muscular dystrophy, whereas only females
whose X chromosomes both carry the mutation will develop the disease. What is the probability that a child will develop the disease? Round your answer to five
decimal places.
Answer:

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