Calculate [OH ], [H*], and the pH of 0.41 M solutions of each of the following amines (K, for aniline is 3.8 × 10-10, K½ for methylamine is 4.38 × 104). a. aniline [OH¯] =[ м [H*] = [ pH = b. methylamine [OH¯] = [ |M [H*] =[ M pH =

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**Calculation of Hydroxide Ion Concentration \([OH^-]\), Hydrogen Ion Concentration \([H^+]\), and pH of Amine Solutions**

On this page, we demonstrate the process of calculating \( [OH^-] \), \( [H^+] \), and the pH of 0.41 M solutions of two different amines. We use the base dissociation constants (\( K_b \)) for each amine to facilitate these calculations.

Given:
- For aniline: \( K_b = 3.8 \times 10^{-10} \)
- For methylamine: \( K_b = 4.38 \times 10^{-4} \)

### a. Aniline

1. **Hydroxide Ion Concentration \([OH^-]\)**:
   
   Input area for result: \_\_\_\_\_\_ M

2. **Hydrogen Ion Concentration \([H^+]\)**:

   Input area for result: \_\_\_\_\_\_ M

3. **pH**:

   Input area for result: \_\_\_\_\_\_

### b. Methylamine

1. **Hydroxide Ion Concentration \([OH^-]\)**:
   
   Input area for result: \_\_\_\_\_\_ M

2. **Hydrogen Ion Concentration \([H^+]\)**:
   
   Input area for result: \_\_\_\_\_\_ M

3. **pH**:
   
   Input area for result: \_\_\_\_\_\_

For each amine, you can calculate the hydroxide ion concentration \([OH^-]\) using the \( K_b \) value and the initial concentration of the amine solution. Once \([OH^-]\) is determined, you can calculate \([H^+]\) using the water dissociation constant \( K_w = 1.0 \times 10^{-14} \) at 25°C. Finally, the pH of the solution can be calculated using the formula:

\[ \text{pH} = -\log [H^+] \]

This framework helps in understanding the influence of different \( K_b \) values on the pH of amine solutions.
Transcribed Image Text:**Calculation of Hydroxide Ion Concentration \([OH^-]\), Hydrogen Ion Concentration \([H^+]\), and pH of Amine Solutions** On this page, we demonstrate the process of calculating \( [OH^-] \), \( [H^+] \), and the pH of 0.41 M solutions of two different amines. We use the base dissociation constants (\( K_b \)) for each amine to facilitate these calculations. Given: - For aniline: \( K_b = 3.8 \times 10^{-10} \) - For methylamine: \( K_b = 4.38 \times 10^{-4} \) ### a. Aniline 1. **Hydroxide Ion Concentration \([OH^-]\)**: Input area for result: \_\_\_\_\_\_ M 2. **Hydrogen Ion Concentration \([H^+]\)**: Input area for result: \_\_\_\_\_\_ M 3. **pH**: Input area for result: \_\_\_\_\_\_ ### b. Methylamine 1. **Hydroxide Ion Concentration \([OH^-]\)**: Input area for result: \_\_\_\_\_\_ M 2. **Hydrogen Ion Concentration \([H^+]\)**: Input area for result: \_\_\_\_\_\_ M 3. **pH**: Input area for result: \_\_\_\_\_\_ For each amine, you can calculate the hydroxide ion concentration \([OH^-]\) using the \( K_b \) value and the initial concentration of the amine solution. Once \([OH^-]\) is determined, you can calculate \([H^+]\) using the water dissociation constant \( K_w = 1.0 \times 10^{-14} \) at 25°C. Finally, the pH of the solution can be calculated using the formula: \[ \text{pH} = -\log [H^+] \] This framework helps in understanding the influence of different \( K_b \) values on the pH of amine solutions.
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