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Q: The equilibrium constant, K, for the following reaction is 9.52×102 at 350 K: CH4(g) +…
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A: Information about the question
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A: The explanation is given below-
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A: Description: Equilibrium reaction is given:
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Q: For the equilibrium: 2 BrCl (g) --> Br2 (g) + Cl2 (g) at 205 °C, the equilibrium constant, Kc, is…
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Q: At a certain temperature, the equilibrium constant K for the following reaction is 1.1: Cl₂(g) +…
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Q: At a certain temperature, the equilibrium constant K for the following reaction is 3.44 x 10°:…
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Q: A mixture of 0.10 mole NO, 0.050 mole H₂, and 0.10 mole H₂O is placed in a 2.0 L vessel. The…
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Q: Suppose a 500. mL flask is filled with 0.30 mol of Br,, 1.5 mol of OCl, and 1.0 mol of BrOCl. The…
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Q: At a certain temperature, the equilibrium constant K for the following reaction is 6.8 × 10°: Cl,(2)…
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Q: Consider the following equilibrium system at 355 K. 2NOBr(g) -----> 2NO(g)+Br2(g). If an equilibrium…
A: [NOBr] = 3.21 x 10-2 M [NO] = 2.01 x 10-2 M [Br2] = 3.98 x 10-2 M Keq = ?
Q: Suppose a 500. mL flask is filled with 0.30 mol of Br₂, 1.2 mol of OCI, and 0.60 mol of BrCl. The…
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The following reaction is important in the manufacture of sulfuric acid:
SO2(g)+1/2 O2(g)->SO3(g)
At a certain temperature, 3.61 x10^-2 mol of SO2 and 3.68X10^-2 mol of O2 are sealed in a 1.00-L reaction vessel. When equilibrium is reached, the concentration of SO3 is determined to be 2.98X10^-2. Calculate Kc for this reaction.
Kc=
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- Using the general properties of equilibrium constants 0/5 At a certain temperature, the equilibrium constant K for the following reaction is 7.4 × 10 ': N,(e) + 0,(g) -2NO(g) Use this information to complete the following table. Suppose a 35. L reaction vessel is filled with 1.7 mol of NO. What can you say about the composition of the mixture in the vessel at equilibrium? O There will be very little N, and 0,. O There will be very little NO. O Neither of the above is true. What is the equilibrium constant for the following reaction? Round your answer to 2 significant digits. K =] 2 NO(g) N2(0)+O2(a) 1, What is the equilibrium constant for the following reaction? Round your answer to 2 significant digits. K = ] 2N,(0)+20,(0) 4 NO(g) 1,At a certain temperature, the equilibrium constant K for the following reaction is 0.71: N2(g) + O2(g) =2 NO(g) Use this information to complete the following table. Suppose a 43. L reaction vessel is filled with 1.0 mol of NO. What can you say about the composition of the mixture in the vessel at equilibrium? There will be very little N2 and 02. There will be very little NO. Neither of the above is true. What is the equilibrium constant for the following reaction? Be sure your answer has the correct number of significant digits. K =0 2 NO(g) N,(9)+O2(9) What is the equilibrium constant for the following reaction? Be sure your answer has the correct number of significant digits. K = 3 N2(9)+30,(9) 6 NO(g)Calculating an equilibrium constant from a partial equilibrium composition Steam reforming of methane (CH4) produces "synthesis gas," a mixture of carbon monoxide gas and hydrogen gas, which is the starting point for many important industrial chemical syntheses. An industrial chemist studying this reaction fills a 75.0 L tank with 35. mol of methane gas and 16. mol of water vapor, and when the mixture has come to equilibrium measures the amount of hydrogen gas to be 43. mol. Calculate the concentration equilibrium constant for the steam reforming of methane at the final temperature of the mixture. Round your answer to 2 significant digits. K = [] с x10 X Ś ? olo 18 Ar
- Steam reforming of methane ( CH, ) produces "synthesis gas," a mixture of carbon monoxide gas and hydrogen gas, which is the starting point for many important industrial chemical syntheses. An industrial chemist studying this reaction fills a 5.0 L flask with 0.93 atm of methane gas and 2.7 atm of water vapor, and when the mixture has come to equilibrium measures the partial pressure of carbon monoxide gas to be 0.47 atm. Calculate the pressure equilibrium constant for the steam reforming of methane at the final temperature of the mixture. Round your answer to 2 significant digits. K_ = || x10Suppose a 250. mL flask is filled with 1.2 mol of Br,, 1.4 mol of OCl, and 1.1 mol of BrCl. The following reaction becomes possible: Br, (g) +OCl, (g) - BrOC1 (g) +BrC1(g) The equilibrium constant K for this reaction is 0.483 at the temperature of the flask. Calculate the equilibrium molarity of OCl,. Round your answer to two decimal places. OMSuppose a 250. mL flask is filled with 1.6 mol of Br₂, 0.70 mol of OC12 and 0.50 mol of BrCl. The following reaction becomes possible: Br₂(g) + OC1₂(g) → BrOC1 (g) + BrCl(g) The equilibrium constant K for this reaction is 2.87 at the temperature of the flask. Calculate the equilibrium molarity of Br₂. Round your answer to two decimal places. M Ś
- A gaseous mixture contains 0.27 mol CO, 0.12 mol H2, and 0.022 mol H,O, plus an unknown amount of CH4, in each liter. This mixture is at equilibrium at a certain temperature. CO(9) + 3H, (9) = CH4 (9) + H,O(9) What is the concentration of CH4 in this mixture? The equilibrium constant K, equals 3.99.Using the general properties of equilibrium constants At a certain temperature, the equilibrium constant K for the following reaction is 924.: CO(g) + H₂O(g) → CO₂(g) + H₂(g) Use this information to complete the following table. Suppose a 17. L reaction vessel is filled with 0.75 mol of CO₂ and 0.75 mol of H₂. What can you say about the composition of the mixture in the vessel at equilibrium? What is the equilibrium constant for the following reaction? Round your answer to 3 significant digits. CO₂(g) + H₂(9) CO(g)+H₂O(g) What is the equilibrium constant for the following reaction? Round your answer to 3 significant digits. 3 CO(g) + 3H₂O(g) P 3 CO₂(g) + 3H₂(9) There will be very little CO and H₂O. There will be very little CO2 and H₂. Neither of the above is true. K = 0 K = 0 ■ x10 X ? 00. Ar 8.Suppose a 500. mL flask is filled with 0.20 mol of Br,, 1.6 mol of OCl, and 1.9 mol of BrOCl. The following reaction becomes possible: 2' Br, (g) +OCl, (g)- BROCI(g)+BrC1(g) The equilibrium constantK for this reaction is 5.57 at the temperature of the flask. Calculate the equilibrium molarity of BrOCl. Round your answer to two decimal places. O M
- Phosphorus pentachloride decomposes according to the chemical equation PC15(g) PC13(g) + Cl₂(g) Kc = 1.80 at 250 °C A 0.1584 mol sample of PC1, (g) is injected into an empty 2.00 L reaction vessel held at 250 °C. Calculate the concentrations of PCl, (g) and PC13 (g) at equilibrium.Using the general properties of equilibrium constants At a certain temperature, the equilibrium constant k for the following reaction is 9.84 x 101: N,(g) + 0,(g) = 2 NO(g) Use this information to complete the following table. Suppose a 30. L reaction vessel is filled with 0.64 mol of N2 and There will be very little N, and O2. alo 0.64 mol of 0,. What can you say about the composition of the mixture in the vessel at equilibrium? There will be very little NO. Neither of the above is true. What is the equilibrium constant for the following reaction? Round your answer to 3 significant digits. K 2 NO(g) N3(9)+Og(9) What is the equilibrium constant for the following reaction? Round your answer to 3 significant digits. K = 3 N,(9)+30,(9) 6 NO(g)N2(g) and O2(g) can exist in equilibrium with NO(g), as shown below. The equilibrium constant at 25.0°C is 4.8 x 10-31. If initially there are 1.35 mol of nitrogen and 0.60 mol of oxygen in a 2.00 L vessel, find the equilibrium concentrations of each species. N2(g) + O2(g) → 2NO(g)
