Calculate ΔH°25° for the reaction: Fe3O4(s)+2 C(s, graphite)  = 3 Fe(s) + CO2(g) from the following data: 2 Fe(s)+3/2 O2(g) = Fe2O3(s)             ΔH°25°c= -826 kJ Fe(s)+1/2 O2(g)= FeO(s)                     ΔH°25°c= -272 kJ FeO(s)+Fe2O3(s)= Fe3O4(s)              ΔH°25°c= -1121 kJ C(s, graphite)+ CO2(g)= CO2(g)         ΔH°25°c= -394 kJ

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Calculate ΔH°25° for the reaction: Fe3O4(s)+2 C(s, graphite)  = 3 Fe(s) + CO2(g) from the following data:

2 Fe(s)+3/2 O2(g) = Fe2O3(s)             ΔH°25°c= -826 kJ

Fe(s)+1/2 O2(g)= FeO(s)                     ΔH°25°c= -272 kJ

FeO(s)+Fe2O3(s)= Fe3O4(s)              ΔH°25°c= -1121 kJ

C(s, graphite)+ CO2(g)= CO2(g)         ΔH°25°c= -394 kJ

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