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Calculate amount of vitamin c in sample (mg) and concentration of vitamin c (mg/ml). Given: DCIP (0.1mg/ml water), Molar mass of DCIP= 268.1 g/mol Molar mass of ascorbic acid (vitamin c)= 176.12 g/mol

Calculate amount of vitamin c in sample (mg) and concentration of vitamin c (mg/ml). Given: DCIP (0.1mg/ml water), Molar mass of DCIP= 268.1 g/mol Molar mass of ascorbic acid (vitamin c)= 176.12 g/mol

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ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
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Calculate amount of vitamin c in sample (mg) and concentration of vitamin c (mg/ml). 

Given: DCIP (0.1mg/ml water), 

Molar mass of DCIP= 268.1 g/mol 

Molar mass of ascorbic acid (vitamin c)= 176.12 g/mol

 

Titration Heating Volume of DCIP (ml) Average Amt of Conc of # time vol of Vit C in Vit C DCIP Sample (mg) (min) (mg/ml) Initial Final Difference (ml) la 26.30 34.60 8.3 7.45 0.15 0.03 1b 34.60 41.25 6.65 2a 5 26.0 31.50 5.5 5.375 2b 5 31.5 36.75 5.25 За 15 41.25 46.15 4.9 4.925 3b 15 15.8 20.75 4.95 4a 30 36.75 41.10 4.35 3.80 4b 30 41.10 44.35 3.25
Transcribed Image Text:Titration Heating Volume of DCIP (ml) Average Amt of Conc of # time vol of Vit C in Vit C DCIP Sample (mg) (min) (mg/ml) Initial Final Difference (ml) la 26.30 34.60 8.3 7.45 0.15 0.03 1b 34.60 41.25 6.65 2a 5 26.0 31.50 5.5 5.375 2b 5 31.5 36.75 5.25 За 15 41.25 46.15 4.9 4.925 3b 15 15.8 20.75 4.95 4a 30 36.75 41.10 4.35 3.80 4b 30 41.10 44.35 3.25
Expert Solution
Step 1

Each cm3 of 1% DCIP solution equvalent to 6.071× 10^-4 g ascorbic Acid.

268.1gm DCIP=1Mol

0.1/1000=0.0001gm=(1/268.1)×0.0001mol =3.73×10-7M

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