A solution consisting of 1.1 M NaNO3 and 2.0 M Ca(NO3)2- concentration: osmol/L

Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
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**Solution Concentration Calculation**

The problem involves a solution composed of two components: 1.1 M NaNO₃ (sodium nitrate) and 2.0 M Ca(NO₃)₂ (calcium nitrate).

To determine the osmolarity of the solution, we need to calculate the total number of osmoles contributed by each solute.

**NaNO₃:**
- Each NaNO₃ dissociates into two ions: Na⁺ and NO₃⁻.
- Therefore, 1.1 M NaNO₃ results in 1.1 x 2 = 2.2 osmoles/L.

**Ca(NO₃)₂:**
- Each Ca(NO₃)₂ dissociates into three ions: Ca²⁺ and 2 NO₃⁻.
- Thus, 2.0 M Ca(NO₃)₂ results in 2.0 x 3 = 6.0 osmoles/L.

**Total Osmolarity:**
- Sum of osmoles from both solutes: 2.2 + 6.0 = 8.2 osmoles/L.

The concentration box is intended for this calculated osmolarity value:

**Concentration: 8.2 osmol/L**
Transcribed Image Text:**Solution Concentration Calculation** The problem involves a solution composed of two components: 1.1 M NaNO₃ (sodium nitrate) and 2.0 M Ca(NO₃)₂ (calcium nitrate). To determine the osmolarity of the solution, we need to calculate the total number of osmoles contributed by each solute. **NaNO₃:** - Each NaNO₃ dissociates into two ions: Na⁺ and NO₃⁻. - Therefore, 1.1 M NaNO₃ results in 1.1 x 2 = 2.2 osmoles/L. **Ca(NO₃)₂:** - Each Ca(NO₃)₂ dissociates into three ions: Ca²⁺ and 2 NO₃⁻. - Thus, 2.0 M Ca(NO₃)₂ results in 2.0 x 3 = 6.0 osmoles/L. **Total Osmolarity:** - Sum of osmoles from both solutes: 2.2 + 6.0 = 8.2 osmoles/L. The concentration box is intended for this calculated osmolarity value: **Concentration: 8.2 osmol/L**
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