Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Question
100%
How would you prepare 100ml of 0.5m solution using stock solution?
please explain your answer

Transcribed Image Text:Introduction
A 1.0 M solution contains 1 mole of that substance in 1 liter of solution, and a 1.0 N solution contains
1 equivalent weight of substance per liter of solution.
Since the molecular weights of Na = 22.99 and Cl = 35.45
For NaCl, one mole = 1 equivalent weight = 58.44 g
%3D
Therefore 1M solution = 58.44 gm of NaCl dissolved in 1 liter of distilled water or
5.844 gm of NaCl dissolved in 100 ml of distilled water

Transcribed Image Text:Solution A
1. Using a pipette pump, and a 10ml pipette, transfer 10ml of the stock solution to another
volumetric flask
2. Make up to the 100ml mark with distilled water, stopper the flask and shake well.
Since this a ten times dilution the, Molarity of this solution is
Solution B
1. Using a pipette pump, and a 10ml pipette, transfer 10ml of the Solution A to another
volumetric flask
2. Make up to the 100ml mark with distilled water, stopper the flask and shake well.
Since this a ten times dilution the, Molarity of this solution is =
M
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Would the molarity of NaCl change if it had 1 gram of sugar in the solution as well? Explain your answer
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