O Calculate the number of milliliters of 0.686 M Ba(OH)2 required to precipitate all of the Cu²+ ions in 171 mL of 0.502 M Cul2 solution as Cu(OH)2. The equation for the reaction is: Cul₂ (aq) + Ba(OH)2 (aq) → Cu(OH)2 (s) + Bal₂ (aq) Volume = mL
O Calculate the number of milliliters of 0.686 M Ba(OH)2 required to precipitate all of the Cu²+ ions in 171 mL of 0.502 M Cul2 solution as Cu(OH)2. The equation for the reaction is: Cul₂ (aq) + Ba(OH)2 (aq) → Cu(OH)2 (s) + Bal₂ (aq) Volume = mL
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Please answer both questions
![**Precipitation Reaction Calculation**
Calculate the number of milliliters of 0.686 M Ba(OH)₂ required to precipitate all of the Cu²⁺ ions in 171 mL of 0.502 M CuI₂ solution as Cu(OH)₂.
The equation for the reaction is:
\[ \text{CuI}_2(aq) + \text{Ba(OH)}_2(aq) \rightarrow \text{Cu(OH)}_2(s) + \text{BaI}_2(aq) \]
**Volume = [ ] mL**
In this experiment, you are tasked with determining the volume of barium hydroxide solution needed to completely precipitate copper ions from a copper(I) iodide solution, converting them into copper(II) hydroxide, a solid. Use the balanced chemical equation to understand the stoichiometry of the reaction, ensuring proper calculation of milliliters needed.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F4295bf62-da14-49f1-b3bf-6e678bc68de3%2F0c533a7c-efd0-4f3c-ab7f-b779a2d6f6ff%2Fa4a4j8r_processed.jpeg&w=3840&q=75)
Transcribed Image Text:**Precipitation Reaction Calculation**
Calculate the number of milliliters of 0.686 M Ba(OH)₂ required to precipitate all of the Cu²⁺ ions in 171 mL of 0.502 M CuI₂ solution as Cu(OH)₂.
The equation for the reaction is:
\[ \text{CuI}_2(aq) + \text{Ba(OH)}_2(aq) \rightarrow \text{Cu(OH)}_2(s) + \text{BaI}_2(aq) \]
**Volume = [ ] mL**
In this experiment, you are tasked with determining the volume of barium hydroxide solution needed to completely precipitate copper ions from a copper(I) iodide solution, converting them into copper(II) hydroxide, a solid. Use the balanced chemical equation to understand the stoichiometry of the reaction, ensuring proper calculation of milliliters needed.
![**Problem Statement:**
Calculate the volume (in mL) of a 0.773 M HNO₃ solution required to completely dissolve 8.42 g of MgCO₃.
**Chemical Reaction:**
\[ 2\text{HNO}_3(aq) + \text{MgCO}_3(s) \rightarrow \text{Mg(NO}_3\text{)}_2(aq) + \text{H}_2\text{O}(l) + \text{CO}_2(g) \]
**Solution Blank:**
\[ \boxed{\phantom{0000}} \text{ mL} \]](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F4295bf62-da14-49f1-b3bf-6e678bc68de3%2F0c533a7c-efd0-4f3c-ab7f-b779a2d6f6ff%2Fis6sne8_processed.jpeg&w=3840&q=75)
Transcribed Image Text:**Problem Statement:**
Calculate the volume (in mL) of a 0.773 M HNO₃ solution required to completely dissolve 8.42 g of MgCO₃.
**Chemical Reaction:**
\[ 2\text{HNO}_3(aq) + \text{MgCO}_3(s) \rightarrow \text{Mg(NO}_3\text{)}_2(aq) + \text{H}_2\text{O}(l) + \text{CO}_2(g) \]
**Solution Blank:**
\[ \boxed{\phantom{0000}} \text{ mL} \]
Expert Solution

Step 1
a) given,
CuI2(aq) + Ba(OH)2 -----> Cu(OH)2(s) + BaI2(aq)
For Ba(OH)2 solution:
Concentration of Ba(OH)2 solution = 0.686 M = 0.686 mol/L
Volume of Ba(OH)2 solution = ?
For CuI2 solution:
Concentration of CuI2 solution = 0.502 M = 0.502 mol/L
Volume of CuI2 solution = 171 mL = 0.171 L
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