**Thermodynamics Reaction Calculations**Enter your answer in the provided box.**Calculate ΔH°rxn for the following reaction:**\[ \text{SiO}_2(s) + 4 \text{HF}(g) \rightarrow \text{SiF}_4(g) + 2 \text{H}_2\text{O}(l) \]**Given Standard Enthalpies of Formation (ΔH°f):**- ΔH°f [SiO2 (s)] = -910.9 kJ/mol- ΔH°f [HF (g)] = -273 kJ/mol- ΔH°f [SiF4 (g)] = -1614.9 kJ/mol- ΔH°f [H2O (l)] = -285.840 kJ/mol**[Input Box for Answer]** (kJ)*Note: No graphs or diagrams are present in this text.*

Calculate enthalpy of the given reaction by using the data given--

Answered: Calculate AH for the following: rxn…

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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Consider the following reactions: AH = -393.5 kJ (graphite) + 2 AH = -285.8 kJ 2(g) CH,OH + 3/2 0, +2H,0 AH = -726.4 k (1) Choose... Choose... -48.25 Calculate the enthalpy change for the following reaction: 188.7 + 2 H29) CH,OH -37.6 C (graphite) + V½ 0, 10.7 -238.7 39.0 268 11.85 Given the following information: N, bond energy = 941 kJ/mol, F, bond energy = 154 kJ/mol 2 N + 3/2 F AH = -103 kJ/mol 2(g) Choose... Calculate the N-F bond energy (kJ/mol) A ballon originally had a volume of 8.68 L at 258 K and a pressure of 575 mmHg. To what temperature (in K) must the balloon be cooled to reduce its volume to 5.00 L at a pressure of 730 mmHg? Choose... V
Given the reactions, X(s) + 1/2O₂(g) XCO₂ (s) XO(s) XO(s) + CO₂(g) what is AH for this reaction? X(s) + 1/2O₂(g) + CO₂(g) AH = -763.1 kJ AH = +159.3 kJ XCO3(s)
18. From the following data, AH = -393.5 kJ/mol C(graphite) + O₂(g) → CO₂(g) 1 H₂ (g) + O₂(g) → H₂O(l) AH = -285.8 kJ/mol 2C₂H6 (g) +70₂(g) → 6H₂O(l) + 4CO₂(g) AH = -3119.06 kJ/mol calculate the enthalpy change for the reaction: 2C (graphite) (1) + 3H₂(g) → 2C₂H6 (g)
4.From these data: N2H4(l) + O2(g) à 2N2(g) + 2H2O(l) H= -622.2 kJ/mol H2(g) + ½O2 à H2O(l) H= -285.8 kJ/mol H2(g) + O2(g) à H2O2(l) H= -115 kJ/mol Find H for the reaction: N2H4(l) + 2H2O2(l) à 2N2(g) + 4H2O(l)
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04) (g Calculate the volume of air at 30°C and 1.00 atm that is needed to burn completely 10.0 grams of propane. Assume that air is 21.0 percent O₂ by volume. The heat of combustion of propane is -2,220.1 kJ/molrxn. Calculate the heat of formati of propane given that AHO of H₂0(1) = -285.3 kJ/mol and AHO of CO2(g) = -393.5 kJ/ f AH-[(3•Co₂) + (4•H₂0)]-[C3H8 + 5(0₂)] [ F)+(4(-285.3)]-[AH C3H5] [200
Given the following data, calculate the enthalpy of formation for H2O2 (AH of H202(0)) H2O2(()* O2(g) + H20(!) 2 AH = -99 kJ -> 2 H2(g) + O2(g) 2 H20(!) AH = -572 kJ
Calculate AH, (kJ/mol), enthalpy of formation, for the hypothetical CaF(s) given: AHjattice = -795 kJ/mol AHsub(Ca) = +178 kJ/mol AHje1 (Ca) = +590 kJ/mol %3D AHje2 (Ca) = +1250 kJ/mol AH(F2) = +158 kJ/mol AHea(F) = -328 kJ/mol 1053 O -974 O 874 O 974 O 1053
Given the following reactions: N2 (g) + O2 (g) → 2NO (g) AH = +180.7 kJ 2N20 (g) → O2 (g) + 2N2 (g) AH = -163.2 kJ the enthalpy of reaction for 2N20 (g) → 2NOo (g) + N2 (g) is kJ. -343.9 343.9 -145.7 145.7 O 17.5
Using the AH -50 kJ/mmol, calculate the enthalpy change if you neutralized six moles of HCl with an equal number of moles NaOH to ONE DECIMAL PLACE WITHOUT UNITS
Calculate AH for the following reaction, given the data in the table below: 4N204 (2) →2N20g) + 4NO2 (g) + 302 AH = ??? kJ/mol 2NO2 (e) + 2NO() +O2 (g)→2N2O4 (g) AH = -396.81 kJ 4NO+ 2N2Og) + 502 (g)→4N2O4 (g) AH = -398.88 kJ 2NO + O2 ()→N2O4 (3) AH = -173.09 kJ

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Calculate AH for the following: rxn SiO2(s) + 4 HF(g) SiF (g) + 2 H,0() AH (SIO2 (s)]=-910.9 kJ/mol AH HF (g)] =-273 kJ/mol %3D AH [SIF (g)] =-1,614.9 kJ/mol f AH H O (1)] =-285.840 kJ/mol f kJ