Calculate AG and K at 25°C for the reactions.7H20 +2 Cr** +3 Cl2 Cr2 0,2- +6 Cl +14H+= 0.03 Va.EcellAG° =kJK =Cu2+(aq)+Ba(s) Ba2+ (ag) + Cu(s) e = 3.24 Vb.AG =kJK =Cl2 (g) + 2 Br (ag) = Br2 (g) +2 Cl¯(aq) e° = 0.27 Vc.AGkJK =d.3H20(1) +5 IO, (ag)+2 Mn²+ (aq) 5103 (aq) + 2 MnO4 (aq) + 6H (aq)Eell = 0.09 VAGkJK =

Since you have posted question with multiple sub-parts, we are entitled to answer the first 3 only.…

Calculate AG and K at 25°C for the reactions. 7H2O +2 Cr** +3 Cl2 Cr2 O,2- +6 Cl +14H e = 0.03 V E cell a. %D AG kJ %3D K %3D b. Cu** (aq) + Ba(s) Ba?+ (aq) + Cu(s) e = 3.24 V AG kJ %3D K= %3D c. Cl2 (g) + 2 Br (aq) Br2 (g) + 2 Cl¯(aq) e = 0.27 V AG kJ %3D K %3D

Calculate AG and K at 25°C for the reactions. 7H2O +2 Cr +3 Cl2 Cr2 O,2- +6 Cl +14H e = 0.03 V E cell a. %D AG kJ %3D K %3D b. Cu (aq) + Ba(s) Ba?+ (aq) + Cu(s) e = 3.24 V AG kJ %3D K= %3D c. Cl2 (g) + 2 Br (aq) Br2 (g) + 2 Cl¯(aq) e = 0.27 V AG kJ %3D K %3D

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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Question

Calculate AG and K at 25°C for the reactions.
7H20 +2 Cr** +3 Cl2 Cr2 0,2- +6 Cl +14H+
= 0.03 V
a.
Ecell
AG° =
kJ
K =
Cu2+
(aq)+Ba(s) Ba2+ (ag) + Cu(s) e = 3.24 V
b.
AG =
kJ
K =
Cl2 (g) + 2 Br (ag) = Br2 (g) +2 Cl¯(aq) e° = 0.27 V
c.
AG
kJ
K =
d.
3H20(1) +5 IO, (ag)+2 Mn²+ (aq) 5103 (aq) + 2 MnO4 (aq) + 6H (aq)
Eell = 0.09 V
AG
kJ
K =

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Calculate AG° and K at 25°C for the reactions. 7H2O + 2 Cr+ + 3 Cl2 = Cr2 07²- + 6 Cl¯ + 14H = 0.03 V cel a. AG° = kJ K = Cu²+ (aq) + Ba(s) = Ba2+ (aq) + Cu(s) e° = 3.24 V b. AG° : kJ K = Cl2 (g) + 2 Br (aq) = Br2 (g) + 2 Cl¯ (ag) e° = 0.27 V C. AG° = kJ K = 3H2 O(1) + 5 IO4 (ag) + 2 Mn²+ (aq) = 5 IO3 (aq) + 2 MnO4¯(ag) + 6H† (ag) d. 0.09 V ´cell AG° = kJ K =
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