Calcium carbonate, CaCO3, reacts with hydrochloric acid as shown in the equation below CACO3(s) + + 2HCI (aq) CaCiz(aq) + H,O(1) + CO(g) 7.50 x 10 mol CACO3 reacts s with 0.200 mol dm3 HCI. (i) Calculate the volume, in cm3, of 0.200 mol dm HCI required to react with 7.50 x 10 mol CaCO3. Volumes moles Concen -0.0375 るへ lo00 am 0.200 375. answer = (i) Calculate the volume, in cm, of CO2 formed at room temperature and pressure.

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Please answer the questions i and ii ignoring my answer 

750 Xl6-
Calcium carbonate, CaCO3, reacts with hydrochloric acid as shown in the equation below
CACO3(s) + 2HCI (aq)
→ CaCl2(aq) + H2O(1) + CO-(g)
7.50 x 10 mol CaCO3 reacts with 0.200 mol dm³ HCI.
(i)
Calculate the volume, in cm3, of 0.200 mol dm HCI required to react
with 7.50 x 10 mol CaCO.
Volume=
moles
=0.0375m
1)
concen
0.200
375
xlo00
cm²
answer =
(ii) Calculate the volume, in cm, of CO2 formed at room temperature and pressure.
cm
answer =
Transcribed Image Text:750 Xl6- Calcium carbonate, CaCO3, reacts with hydrochloric acid as shown in the equation below CACO3(s) + 2HCI (aq) → CaCl2(aq) + H2O(1) + CO-(g) 7.50 x 10 mol CaCO3 reacts with 0.200 mol dm³ HCI. (i) Calculate the volume, in cm3, of 0.200 mol dm HCI required to react with 7.50 x 10 mol CaCO. Volume= moles =0.0375m 1) concen 0.200 375 xlo00 cm² answer = (ii) Calculate the volume, in cm, of CO2 formed at room temperature and pressure. cm answer =
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