(c) The ore being placed on the heap has an average copper grade of 1.0% and the lixiviant addition rate is 900 m3 /hr. 5% of the liquid is lost through evaporation and other loses and the pregnant solution contains an average of 2.1 kg Cu/m³. The solvent extraction stage recovers 90% of this copper, with the barren solution having additional acid and water added to make up for the lost volume and consumed material before being added back onto the heap. What is the average recovery of the copper from the heap leaching assuming no losses in the SX/EW?

(c) The ore being placed on the heap has an average copper grade of 1.0% and the lixiviant addition rate is 900 m3 /hr. 5% of the liquid is lost through evaporation and other loses and the pregnant solution contains an average of 2.1 kg Cu/m³. The solvent extraction stage recovers 90% of this copper, with the barren solution having additional acid and water added to make up for the lost volume and consumed material before being added back onto the heap. What is the average recovery of the copper from the heap leaching assuming no losses in the SX/EW?

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

See similar textbooks

Similar questions

Mganga is doing a routine analysis in a copper plating factory. He is regularly making up solutions of verypure CuSO4.5H2O. He suspect that a batch of a reagent used to make up a stock solution of CuSO4.5H2Ois impure and it may contains some CuCl2. He asked you to determine the percentage impurity as follows:Dissolve1.500g of a mixture and make up to 1.00L mark.150mL of this solution was treated with 20.00mLof 0.100M AgNO3 to remove 98.6% of chloride as AgCl precipitate.
Balanced Chemical Equation MnO4- +5Fe2+ +8H+ --> Mn2+ + 5Fe3+ +4H2O Details mass (g) sample average molarity of KMNO4 solution final buret reading initial buret reading volume (mL) of the KMnO4 solution delivered amount (mmoles) KMnO4 needed to reach the end point amount (mmoles) Fe2+ reacted with KMnO4 amount (mmoles) Fe2+(NH4)2 (SO4)2 (6H20) mass (g) Fe2+(NH4)2 (SO4)2 (6H2O) present in the sample %Fe2+(NH4)2 (SO4)2 (6H2O) Trial 1 0.2284 9 mL 0 9 mL 0.18477 0.9239 0.9239 Trial 2 0.2132 0.02053 11 mL 0 11 mL 0.22583 1.1292 1.1292 Trial 3 0.2081 10 mL 0 10 mL 0.2053 1.0265 1.0265
In the common process for the manufacture of nitric acid, sodium nitrate is treated with aq. sulphuric acid containing 95% H2SO4. In order that the resulting "niter cake" may be fluid; it is desirable to use sufficient acid so that there will be 34% H2SO4 by wt in the final cake. This excess H2SO4 will actually be in combination with the Na2SO4 in the cake, forming NaHSO4, although for purposes of computation it may be assumed to be free acid. The cake will contain 1.5% water and the reaction will go to completion, but 2% of the HNO3 formed will remain in the cake. Assume that the NaNO3 used is dry and pure. Calculate per 100 kg of NaNO3 charged: (a) wt and % composition of the niter cake (b) wt of aqueous acid to be used (c) wt of water vapor and nitric acid distilled from the niter cake.
An underfeed stoker feeds coal to a boiler at the rate of 100 kg/hr. The ultimate analysis of coal is: C = 75.2 %, H;= 3.6 %, O2 = 7.4 %, N2 = 1.2 %, S = 2.1 % and the remaining is Ash. The dry refuse taken from the ash pit shows 20 % C and 80 % ash by weight. Orsat analysis of the flue gases gives the following composition, CO2 = 75.2 %, O, = 7.9 %, CO= 1 % Determine: a) m³ of air supplied per minute if the pressure is 100 kPaa and 20 °C; b) Total volume of flue gases flowing through the stack per minute if the temperature is 60 °C and pressure is 100 kPaa.
Calculate the solubility at 25 °C of PbCO3 in pure water and in a 0.0100M Pb(NO3), solution. You'll find Ksp data in the ALEKS Data tab. Round both of your answers to 2 significant digits. 0 // solubility in pure water: x10 solubility in 0.0100 M Pb(NO3)2 0-/- solution: L X 09 00 X S ?
Give me handwritten answer?
You wish to undertake a 100 step countercurrent extraction of solutes A & B with distribution coefficients D= 1.5 & Da - 0.6. Suppose the volumes of mobile and stationary are equal. If fractions 28-40 and 50-68 are each pooled find the % recovery and purity of each solute. AA 79.8% recovery of 99.7% pure A B: 82.0% recovery of 86.6% pure B B. A: 72.7 % recovery of 97.0% pure A B: 89.0 % recovery of 98.9 % pure B OC.A: 82.6% recovery of 92.3% pure A B: 82.9% recovery of 91.0% pure B O D.A 92.6% recovery of 99.5% pure A 8: 67.0% recovery of 100 % pure B
+ + HN in ethyl acetate (organic) treat with aqueous HCI Aqueous layer Organic layer treat with treat with aqueous NaOH; aqueous NaOH collect precipitate by filtration aqueous organic Final product #1 treat with "dry" with MgSO4, filter, evaporate ethyl acetate aqueous HCl; Be sure to label all glass containers of colorless solutions... collect precipitate by filtration It's easy to lose track! Final product #2 Final product #3
A silver-30%gold alloy sample (cylindrical with 1 cm diameter and 0.3 cm height) is subjected to a selective silver dissolution in 0.1 M HNO3 at current density of 2.5 mA/cm2 . How long will it take until the total amount of silver is dissolved? Assume in average a density of 12 g/cm3 for the alloy sample.
Following the monograph procedure, a 724-mg of aspirin (MW=180 g/mol) dissolved in 18.5 ml of cold neutralized alcohol. This solution was then initially titrated with 0.101 N sodium hydroxide solution, then later neutralized with 0.104 sulfuric acid. What is the percentage purity of the sample? 1. What is the milliequivalent weight consumed by the acidic titrant? a. 1.5392 g-meq b. 2.0907 g-meq c. 1.4948 g-meq d. 2.1528 g-meq 2. What is the milliequivalent weight consumed by the basic titrant? a. 5.8656 g-meq b. 1.5392 g-meq c. 5.6964 g-meq d. 1.4948 g-meq 3. What is the difference of milliequivalent weight consumed in the reaction? a. -4.1572 g-meq b. 4.3708 g-meq c. 0.5515 g-meq d. 4.1572 g-meq