You have a stock solution certified by a manufacturer to contain 160.0 + 0.3 pg So,2-/mL. You would like to dilute it by a factor of 100 toobtain 1.600 pg/mL. Two possible methods of dilution are stated below. For each method, calculate the resulting uncertainty in concentration.Use manufacturer's tolerances in the Tolerances of Class A Volumetric Flasks table and Tolerances of ClassA Transfer Pipets table foruncertainties.(a) Dilute 10.00 mL up to 100 mL with a transfer pipet and volumetric flask. Then take 10.00 mL of the dilute solution and dilute it againto 100 mL.ug/mL(b) Dilute 1.000 mL up to 100 mL with a transfer pipet and volumetric flask.pg/mLExplain why one method is more precise than the other.Select- v is more precise because the uncertainty in the 10.00 mL transfer pipet is% and the uncertainty in the1.000 ml transfer pipet is%.

Answered: Image /qna-images/answer/9a12875f-febb-47ad-8fc4-65c72cd0bfe8.jpg

a stock solu in 1.600 pg/mL. Two possible methods of dilution are stated below. For each method, calculate the resulting uncertainty in conc manufacturer's tolerances in the Tolerances of Class A Volumetric Flasks table and Tolerances of Class A Transfer Pipets table for ertainties. (a) Dilute 10.00 mL up to 100 ml with a transfer pipet and volumetric flask. Then take 10.00 mL of the dilute solution and d to 100 mL. 40 Ha/mL (b) Dilute 1.000 mL up to 100 mL with a transfer pipet and volumetric flask. pg/mL lain why one method is more precise than the other. 0.00

a stock solu in 1.600 pg/mL. Two possible methods of dilution are stated below. For each method, calculate the resulting uncertainty in conc manufacturer's tolerances in the Tolerances of Class A Volumetric Flasks table and Tolerances of Class A Transfer Pipets table for ertainties. (a) Dilute 10.00 mL up to 100 ml with a transfer pipet and volumetric flask. Then take 10.00 mL of the dilute solution and d to 100 mL. 40 Ha/mL (b) Dilute 1.000 mL up to 100 mL with a transfer pipet and volumetric flask. pg/mL lain why one method is more precise than the other. 0.00

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

See similar textbooks

Similar questions

A 25mL volumetric pipet is used to deliver a sample of the stock solution marked “0.6000M X2SO4” into a 100mL volumetric flask. Distilled water is added to the flask until it is about 3/4thfull, the solution is mixed well, then more water is added to fill it up to the calibration mark, then it is mixed again. Calculate the concentration of X+ion in the dilute solution made above.
An HPLC method was developed for the separation and determination of ibuprofen in blood samples. A 3.00 mL blood sample dissolved in 70.00 mL solvent was prepared and 10.0 mL was injected into the HPLC. Standard ibuprofen solutions were also run.Calculate the ibuprofen present in the 3.00 mL blood sample The following data were obtained. Table po itoo: Ibuprofen concentration, mg/ml0.50 1.0 2.0 3.0 Blood sample Peak area (Right column)5.29.617.419.911.4
Balanced Chemical Equation MnO4- +5Fe2+ +8H+ --> Mn2+ + 5Fe3+ +4H2O Details mass (g) sample average molarity of KMNO4 solution final buret reading initial buret reading volume (mL) of the KMnO4 solution delivered amount (mmoles) KMnO4 needed to reach the end point amount (mmoles) Fe2+ reacted with KMnO4 amount (mmoles) Fe2+(NH4)2 (SO4)2 (6H20) mass (g) Fe2+(NH4)2 (SO4)2 (6H2O) present in the sample %Fe2+(NH4)2 (SO4)2 (6H2O) Trial 1 0.2284 9 mL 0 9 mL 0.18477 0.9239 0.9239 Trial 2 0.2132 0.02053 11 mL 0 11 mL 0.22583 1.1292 1.1292 Trial 3 0.2081 10 mL 0 10 mL 0.2053 1.0265 1.0265
A water containing 50 mg/L of phosphate (PO,") is flowing in an open channel at a volumetric flow rate (Q) of 2 MGD (million gallons per day). (a) What is the concentration of phosphate expressed in (i) mg/L as PO, --P, (ii) mM as PO., and (iii) mM as PO, P. (b) Find the mass flow rate (S) of phosphate through any section perpendicular to the direction of flow in the open channel expressed in lb/day? Given: Atomic weights: P= 31 g/mole, O = 16 g/mole, 1 gallon = 3.785 L, 1 kg = 2.204 Ib. %3D
i have hard time geting it stright even after I do the experiment can u help me with the one pls Material ChemicalsSealed NO2 tubes, KSCN solution (0.002 M), acidified Fe(NO3)3 solution (0.2 M), KSCN crystals, Fe(NO3)3 crystals, KOH (concentrated (8 M)), distilled waterApparatus:Bunsen burner, ring stand, wire gauze, matches, thermometer, dropper, test tubes, glass stirring rod, beaker tongs Procedure Part A: Fill a 600 mL beaker to the 3/4 mark with water. Bring to a boil using a Bunsen burner. In another 600 mL beaker, fill to the 1/2 mark with water; add ice in order to lower the temperature to about 0°C. Note the room temperature. Observe the NO2 thoroughly at room temperature. Place the sealed NO2 tube in the cold bath. Note your observations. Remove the test tube from the cold bath. Let the test tube stand until it reaches room temperature. Note your observations. Place the test tube in the hot bath. Note your observations. Remove the test tube from the hot bath. Let the test…
A student combined 37.2 mL of 1.69 M KMnO4 solution with 16.60 mL of a 0.891 M KMnO4 solution. Calculate the concentration of the final solution. Tap here r pull up for additional resources Q A 2 W S # 3 E D $ 4 R % 5 F LL Question 5 of 17 T < 60 G Y & 7 H C +00 8 J 1 1 4 7 +/- K 5 C
Given the following data forMass of test tube, beaker and cyclohexane = 100.17 gMass of test tube and beaker = 84.07 gFreezing point of cyclohexane = 6.59 oCMass of weighing paper + naphthalene =1.080 gMass of weighing paper = 0.928 gFreezing point solution = 5.11oCKf = 20.8oC/mDetermine the followinga. mass of cyclohexane in g (2 decimal places); _____b. mass of naphthalene in g (4 decimal places); _____c. freezing point depression (2 decimal places); _____d. molality of solution (3 significant figures); _____e. moles of naphthalene (3 significant figures); _____f. molar mass of naphthalene, experimentally (3 significant figures); _____g. % error if theoretical molar mass of naphthalene is 128.17 g/ mole, USE ABSOLUTE VALUE (3 significant figure); ____
00 mL of a diprotic acid primary standard solution was accurately prepared to a concentration of 0.1431 M. Three samples of this primary standard solution were used as samples in a titration to standardize an aqueous solution of sodium hydroxide, NaOH, which would be used as a titrant. Using the following table of data for the titration of the primary standard acid with NaOH, calculate the average concentration of NaOH. Trial # Volume of primary standard Initial titrant volume Final titrant volume 1 10.00 mL 8.21 mL 27.22 mL 2 10.00 mL 27.22 mL 46.23 mL 3 10.00 mL 30.28 mL 49.29 mL 0.1506 M 0.0753 M 0.0376 M 0.1431 M 0.0526 M
Downvoted for wrong solution. A river is carrying water containing 2000 mg/l Magnesium Chloride into a small lake. The lake has a naturally occurring Magnesium Chloride of 50 mg/l. If the river flow is 2500 Lmin and the lake flow rate is 1.5 m³.sec¹, what is the concentration of MgCl2 in the lake after the discharge point? Assume that the flows in the river and lake are completely mixed, that the salt is a conservative substance, and the system is at steady state.
Mon Apr Content X b Answered: How many mL of X Bb SolutionsQuiz(2) D(175) Destiny's Child S x + thos.content.blackboardcdn.com/5ebc429344443/2748179?X-Blackboard-Expiration=D1619492400000&X-Blackb... Q ☆ be C Home | Chegg.com My Library Brytew... 6 Introductory Che.. 2 / 2 126% + | A How many mL of a 4 M Al(OH)3 solution are needed to reaction with 125 mL of a 2 M HCl solution? 6. Al(OH)3 (s) + 3 HCl (aq) З НСІ → AICI3 (aq) + 3 H2O (1)
A pipet is used to transfer 5.00 mL of a 1.25 M stock solution in flask “S” to a 25.00-mL volumetric flask “B,” which is then diluted with DI H2O to the calibration mark. The solution is thoroughly mixed. Next, 3.00 mL of the solution in volumetric flask “A” is transferred by pipet to a 50.00-mL volumetric flask “B” and then diluted with DI H2O to the calibration mark. Calculate the molarity of the solution in volumetric flask “B.”
Often the analyst will compare known quantities of analyte to unknown quantities of the material to be analyzed. This may be done in one of three ways: -use calibration curves; use standard additions; or use internal standards. The method of standard additions would be used when A) the quantity of sample analyzed or the instrument response varies from run to run. B) the standard solutions and the unknown solution all have similar characteristics are unaffected by the other material in the sample. C) the sample composition is unknown or complex and affects the analytical signal.