C (s) + 02 (g)- CO2 (g) AH° = -393.5 kJ Calculate the heat change if 2.54 g of C is reacted.

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### Thermochemical Equation and Heat Change Calculation

#### Thermochemical Equation:
\[ \text{C(s) + O}_2\text{(g)} \rightarrow \text{CO}_2\text{(g)} \quad \Delta H^\circ = -393.5 \, \text{kJ} \]

#### Problem Statement:
Calculate the heat change if 2.54 g of C is reacted.

### Explanation
This image provides a thermochemical equation representing the combustion of carbon (C) in the presence of oxygen (O₂) to form carbon dioxide (CO₂). The equation specifies that the reaction releases 393.5 kJ of energy per mole of carbon reacted, indicated by the negative sign in \(\Delta H^\circ = -393.5 \, \text{kJ}\).

#### Strategy to Solve:
1. **Find Molar Mass of Carbon (C):**
    \[
    \text{Molar mass of C} = 12.01 \, \text{g/mol}
    \]

2. **Calculate Moles of Carbon:**
    \[
    \text{Moles of C} = \frac{\text{Mass of C}}{\text{Molar mass of C}}
    \]
    \[
    \text{Moles of C} = \frac{2.54 \, \text{g}}{12.01 \, \text{g/mol}} \approx 0.2115 \, \text{mol}
    \]

3. **Calculate the Heat Change:**
    \[
    \Delta H = (\text{Moles of C}) \times (\Delta H^\circ \, \text{per mole of C})
    \]
    \[
    \Delta H = 0.2115 \, \text{mol} \times (-393.5 \, \text{kJ/mol})
    \]
    \[
    \Delta H \approx -83.25 \, \text{kJ}
    \]

### Conclusion
If 2.54 g of carbon are reacted, the heat change for the reaction is approximately \(-83.25 \, \text{kJ}\). This indicates that 83.25 kJ of energy would be released.
Transcribed Image Text:### Thermochemical Equation and Heat Change Calculation #### Thermochemical Equation: \[ \text{C(s) + O}_2\text{(g)} \rightarrow \text{CO}_2\text{(g)} \quad \Delta H^\circ = -393.5 \, \text{kJ} \] #### Problem Statement: Calculate the heat change if 2.54 g of C is reacted. ### Explanation This image provides a thermochemical equation representing the combustion of carbon (C) in the presence of oxygen (O₂) to form carbon dioxide (CO₂). The equation specifies that the reaction releases 393.5 kJ of energy per mole of carbon reacted, indicated by the negative sign in \(\Delta H^\circ = -393.5 \, \text{kJ}\). #### Strategy to Solve: 1. **Find Molar Mass of Carbon (C):** \[ \text{Molar mass of C} = 12.01 \, \text{g/mol} \] 2. **Calculate Moles of Carbon:** \[ \text{Moles of C} = \frac{\text{Mass of C}}{\text{Molar mass of C}} \] \[ \text{Moles of C} = \frac{2.54 \, \text{g}}{12.01 \, \text{g/mol}} \approx 0.2115 \, \text{mol} \] 3. **Calculate the Heat Change:** \[ \Delta H = (\text{Moles of C}) \times (\Delta H^\circ \, \text{per mole of C}) \] \[ \Delta H = 0.2115 \, \text{mol} \times (-393.5 \, \text{kJ/mol}) \] \[ \Delta H \approx -83.25 \, \text{kJ} \] ### Conclusion If 2.54 g of carbon are reacted, the heat change for the reaction is approximately \(-83.25 \, \text{kJ}\). This indicates that 83.25 kJ of energy would be released.
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