c) If the labor capacity of the bakery was 11 man * hour, what would be the maximum value of the total profit? What products would be produced in this case? If necessary, find the new solution with dual simplex.
c) If the labor capacity of the bakery was 11 man * hour, what would be the maximum value of the total profit? What products would be produced in this case? If necessary, find the new solution with dual simplex.
Practical Management Science
6th Edition
ISBN:9781337406659
Author:WINSTON, Wayne L.
Publisher:WINSTON, Wayne L.
Chapter2: Introduction To Spreadsheet Modeling
Section: Chapter Questions
Problem 20P: Julie James is opening a lemonade stand. She believes the fixed cost per week of running the stand...
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this is a linear programming problem. question is in the second image
Transcribed Image Text:c) If the labor capacity of the bakery was 11 man * hour, what would be the maximum
value of the total profit? What products would be produced in this case? If necessary,
find the new solution with dual simplex.
Transcribed Image Text:A bakery makes and sells daily bagels, plain buns and plain soft bagels. It earns 2 TL for each
bagel, 3 TL for a plain bun and 3.25 TL for a plain soft bagel. The bakery aims to produce and
sell at least 100 products per day. The main resources used and the quantities required from
each source for the production of each product are given in the table below.
Bakery Resources
Daily Capacity
Required Resource Amount
Daily Bagel
Plain Bun
Plain Soft
Bagel
Dough (kg)
15
0.10
0.15
0.2
Labor (man*hour)
10.25
0.05
0.15
0.075
Baking Time -
Oven Capacity
20
0.2
0.1
0.2
Utilization
In order to maximize the bakery income, the LP model given below was established. Decision
variables (X1, X2, X3) show the number of daily bagels, plain buns and plain soft bagels
produced per day, respectively. Answer the questions according to this LP model. Find
solutions to sensitivity questions with revised simplex or dual simplex. Unless otherwise
stated, the questions are independent from each other.
Max Z = 2X1 + 3X2 + 3.25X3
S.T.
0.1X1 + 0.15X2 + 0.2X3 S 15
0.05X1 + 0.15X2 + 0.075X3 s 10.25
0.2X1 + 0.1X2 + 0.2X3 s 20
X1+ X2 + X3 2 100
Х, Ха, Xз 2 0
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