C, D, E ** 22. A sled of mass m = 30 kg (including the load sitting on the sled) is pulled by a ropeacross a level field of snow, as shown below. The tension in the rope has a constant magnitudeof 100 newtons and makes an angle of 37° with respect to the horizontal. A friction force of50 N acts on the sled. Follow the steps below to find the acceleration of the sled.RopeT= 100 NSledm = 30 kg37°a) Draw a free-body diagram for the sled. Label each of your forces as described onpages 87-88.b) If any of the forces on your diagram are pointing in some awkward direction (like37° with respect to horizontal), break this force up into a horizontal component (x-part)and a vertical component (y-part).c) Find the magnitude of the gravitational force acting on the sled. (Remember theapproximation g= 10 N/kg.)d) Use Newton's second law and the fact that the sled has no acceleration in the y-direc-tion to solve for the magnitude of the normal force exerted by the snow on the sled.e) Use Newton's second law to find the acceleration of the sled. (Remember the frictionforce!)

c) The magnitude of gravitational force acting on the sled is Fg=mg=30 kg10 ms2=300 N d) The normal…

c) Find the magnitude of the gravitational force acting on the sled. (Remember the approximation g = 10 N/kg.) d) Use Newton's second law and the fact that the sled has no acceleration in the y-direc- tion to solve for the magnitude of the normal force exerted by the snow on the sled. e) Use Newton's second law to find the acceleration of the sled. (Remember the friction force!)

c) Find the magnitude of the gravitational force acting on the sled. (Remember the approximation g = 10 N/kg.) d) Use Newton's second law and the fact that the sled has no acceleration in the y-direc- tion to solve for the magnitude of the normal force exerted by the snow on the sled. e) Use Newton's second law to find the acceleration of the sled. (Remember the friction force!)

University Physics Volume 1

18th Edition

ISBN:9781938168277

Author:William Moebs, Samuel J. Ling, Jeff Sanny

Publisher:William Moebs, Samuel J. Ling, Jeff Sanny

Chapter6: Applications Of Newton's Laws

Section: Chapter Questions

Problem 114AP: A 15-kg sled is pulled across a horizontal, snow-covered surface by a force appiled to a rope at 30...

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Concept explainers

Angular speed, acceleration and displacement

Angular acceleration is defined as the rate of change in angular velocity with respect to time. It has both magnitude and direction. So, it is a vector quantity.

Angular Position

Before diving into angular position, one should understand the basics of position and its importance along with usage in day-to-day life. When one talks of position, it’s always relative with respect to some other object. For example, position of earth with respect to sun, position of school with respect to house, etc. Angular position is the rotational analogue of linear position.

Question

C, D, E

** 22. A sled of mass m = 30 kg (including the load sitting on the sled) is pulled by a rope
across a level field of snow, as shown below. The tension in the rope has a constant magnitude
of 100 newtons and makes an angle of 37° with respect to the horizontal. A friction force of
50 N acts on the sled. Follow the steps below to find the acceleration of the sled.
Rope
T= 100 N
Sled
m = 30 kg
37°
a) Draw a free-body diagram for the sled. Label each of your forces as described on
pages 87-88.
b) If any of the forces on your diagram are pointing in some awkward direction (like
37° with respect to horizontal), break this force up into a horizontal component (x-part)
and a vertical component (y-part).
c) Find the magnitude of the gravitational force acting on the sled. (Remember the
approximation g= 10 N/kg.)
d) Use Newton's second law and the fact that the sled has no acceleration in the y-direc-
tion to solve for the magnitude of the normal force exerted by the snow on the sled.
e) Use Newton's second law to find the acceleration of the sled. (Remember the friction
force!)

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