[°C] = ([°F] - 32) + 1.8 Celsius: To Fahrenheit [°F] = ([°C] × 1.8) + 32 To Kelvin [K] = [°C] + 273.15 Kelvin to Celsius [°C] = [K] – 273.15 For each pair, indicate the wavelength of light with greater energy. a. 1.5x106 m or 1x10-16 m b) 450 nm or 7.5x10-7 m OI. a) 1.5x106 m b) 450 nm O II. none of these O II. a. 1x10-16 m b) 450 nm O V. a) 1.5x106 m b) 7.5x10-7 m O V. a. 1x10-16 m b) 7.5x10-7 m
[°C] = ([°F] - 32) + 1.8 Celsius: To Fahrenheit [°F] = ([°C] × 1.8) + 32 To Kelvin [K] = [°C] + 273.15 Kelvin to Celsius [°C] = [K] – 273.15 For each pair, indicate the wavelength of light with greater energy. a. 1.5x106 m or 1x10-16 m b) 450 nm or 7.5x10-7 m OI. a) 1.5x106 m b) 450 nm O II. none of these O II. a. 1x10-16 m b) 450 nm O V. a) 1.5x106 m b) 7.5x10-7 m O V. a. 1x10-16 m b) 7.5x10-7 m
Chemistry
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ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Please help me calculate the wavelength of line with greater energy. Thanks
![**Temperature Conversions**
**Celsius:**
- **To Fahrenheit**
\[°F = ([°C] \times 1.8) + 32\]
- **To Kelvin**
\[K = [°C] + 273.15\]
**Kelvin to Celsius**
\[°C = [K] - 273.15\]
---
**Question: Wavelength Comparison**
For each pair, indicate the wavelength of light with greater energy.
- **a. \(1.5 \times 10^6\) m or \(1 \times 10^{-16}\) m**
- **b. 450 nm or \(7.5 \times 10^{-7}\) m**
**Options:**
- I.
- a) \(1.5 \times 10^6\) m
- b) 450 nm
- II. none of these
- III.
- a) \(1 \times 10^{-16}\) m
- b) 450 nm
- IV.
- a) \(1.5 \times 10^6\) m
- b) \(7.5 \times 10^{-7}\) m
- V.
- a) \(1 \times 10^{-16}\) m
- b) \(7.5 \times 10^{-7}\) m
---
**Note:** The energy of light is inversely proportional to its wavelength; shorter wavelengths have higher energy.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F1bfdb6c6-6fc3-4de6-b47d-25e0ae945ba0%2F97fe36a3-5393-4fb7-8fb3-f63ea97d23f0%2Fovfkv3q_processed.jpeg&w=3840&q=75)
Transcribed Image Text:**Temperature Conversions**
**Celsius:**
- **To Fahrenheit**
\[°F = ([°C] \times 1.8) + 32\]
- **To Kelvin**
\[K = [°C] + 273.15\]
**Kelvin to Celsius**
\[°C = [K] - 273.15\]
---
**Question: Wavelength Comparison**
For each pair, indicate the wavelength of light with greater energy.
- **a. \(1.5 \times 10^6\) m or \(1 \times 10^{-16}\) m**
- **b. 450 nm or \(7.5 \times 10^{-7}\) m**
**Options:**
- I.
- a) \(1.5 \times 10^6\) m
- b) 450 nm
- II. none of these
- III.
- a) \(1 \times 10^{-16}\) m
- b) 450 nm
- IV.
- a) \(1.5 \times 10^6\) m
- b) \(7.5 \times 10^{-7}\) m
- V.
- a) \(1 \times 10^{-16}\) m
- b) \(7.5 \times 10^{-7}\) m
---
**Note:** The energy of light is inversely proportional to its wavelength; shorter wavelengths have higher energy.
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