Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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![### Problem Statement:
**(1) Calculate the wavelength of an electron traveling with a speed of 2.63 x 10⁶ m/s.**
### Explanation:
To solve this problem, we use the de Broglie wavelength formula:
\[ \lambda = \frac{h}{mv} \]
Where:
- \( \lambda \) is the wavelength.
- \( h \) is Planck's constant (\(6.626 \times 10^{-34} \, \text{Js}\)).
- \( m \) is the mass of the electron (\(9.11 \times 10^{-31} \, \text{kg}\)).
- \( v \) is the speed of the electron (\(2.63 \times 10^6 \, \text{m/s}\)).
By substituting these values into the formula, you can calculate the wavelength of the electron.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Ff405cacd-b73c-4ff5-aae6-a678a4b84912%2F4780d3e6-c273-4e67-92cc-7a36b37e3e79%2Fwfc2pvt_processed.jpeg&w=3840&q=75)
Transcribed Image Text:### Problem Statement:
**(1) Calculate the wavelength of an electron traveling with a speed of 2.63 x 10⁶ m/s.**
### Explanation:
To solve this problem, we use the de Broglie wavelength formula:
\[ \lambda = \frac{h}{mv} \]
Where:
- \( \lambda \) is the wavelength.
- \( h \) is Planck's constant (\(6.626 \times 10^{-34} \, \text{Js}\)).
- \( m \) is the mass of the electron (\(9.11 \times 10^{-31} \, \text{kg}\)).
- \( v \) is the speed of the electron (\(2.63 \times 10^6 \, \text{m/s}\)).
By substituting these values into the formula, you can calculate the wavelength of the electron.
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