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- Evaluate the Reynolds number for flow over a tube from the following data: D=6cm,U=1.0m/s, =300kg/m3,=0.04Ns/m2.Use= Resolving of Example (1-3) Two reservoirs with a difference in elevation of 15 m are connected by the three pipes in series. The pipes are 300 m long of diameter 30 cm, 150 m long of 20 cm diameter, and 200 m long of 25 cm diameter respectively. The friction factors for the three pipes are, respectively, 0.018, 0-020 and 0-019, and which account for friction and all losses. Further the contractions and expansions are sudden. Determine the flow rate in l/s. The loss co-efficient for sudden contraction from dia. 30 cm to 20 cm = 0.24. Le-L₂ (D.) ² Le = L3 (D₁) ² 5 D3 LT. L₁ + L₂ ( D₁ ) ³ + L3 (D²₂) ³ 5 5 D3Water at 303k s flowing at the rate -4 6.3 X10 m²/s of an inside diameter (16) in a pipe having án inside diameter Cib) 52-5mm.' e Reynolds number. Calculate the Given Density of water at 303k water is 0.8cp is 996 kq lm3. Im? Viscosity of
- EX in Asteel of speçific weight cy lin der (1"diametar andiz" Long) (8) =490 1b fI Ft3 fall be Cause of its own weight, at q uniform slig htly 9. rate of on5 HIs in side a tube of larger diameter.A Castor- oil film M = 6x lo -3 16 between t-s Constant thihness and the tube between of %3D is the cylinder Determine the cleamanCe (y) in ft the Cylinder and the tube-If the difference between the liquid levels in two tanks (2.4 m) and pipe of (o.075m) diameter and (15 m) long used between them. What will be the volumetric flow rate of the fluid in the pipe. If fanning friction factor is (0.008) and liquid density 700 kg/m³ and dynamic viscosity 2.2x10-2kg/m.s and the flow was laminar,The losses per unit length pipe^h/l in turbulent flow through small pipe depend upon Velocity, Diameter, Gravity, Dynamic viscosity and Density. Determine the general from of equation.
- An Unknown Liquid (SG. 0.6651) is flowing through a 59m long copper tube with a radius of 2.5mm at a rate of 0.09 kg/s. What is the head loss in meters, and the required pump power of the system in Watts. The Unknown Liquid has a viscosity of 0.2361 cpsDiscussion 1- Indicate the factors affecting the Reynotes number (Re). 2. The limits are gaved to the Reynolds number (Re) that if they less than 2000 it is the laminar flow and if they more than 4000 The flow is turbubent but there is a possibility to change those limits. 3-Discuss the importance of the infinite medium. Worksheet No. Risc of W.L. in Time for Risc in Collecting Tank (cm) W.L. (sec.) 1 s 45 2 s 26.5 3 s 21.5 4 % 12.75 s s 7 6 s s Diameter of pipe = 1.8 cm Length of pipe = 87 cm Area of Collecting Tank = 13 x 8.5 cm® @ Temperature of water = 30H.W. Petroleum oil (sp. gr. = 0.9 and viscosity = 13 CP) flows isothermally through a horizontal 5 cm pipe. A Pitot tube is inserted at the centre of a pipe and its leads are filled with the same oil and attached to a U-tube containing water. The reading on the manometer is 10 cm. Calculate the volumetric flow of oil in m/s. The co-efficient of Pitot tube is
- A pipe is often used to assess the flow rate of water in the center of a pipe with an internal diameter of 102.3 mm at 20°C (density = 998.3 kg/m3, viscosity = 1.005 CP). The pitot tube coefficient is 0.98, and the manometer reading is 10 mm of mercury at 20°C (density = 13,545. 85 kg/m3). Compute the velocity at the center and the water's volumetric flow rateOil flows at 55.9L/s in a pipe of 160mm diameter and 50m length. SG of oil is 0.9 and viscosity is 0.04 Pa-sec. If head loss is 5.22m, determine: a. Mean Velocity of flow (m/s) b. Type of flow c. Friction Factor d. Velocity at the centerline of pipe (m/s) e. The shear stress at the wall of the pipe (Pa)You are asked to calculate the pressure drop in a straight pipe. Air of density 1.225 kg/m³ is flowing through the pipe. The diameter of the pipe is 25 mm. The velocity of the flow is 1 m/s. The viscosity of air is given as 1.85 x 10-5 Pas. From this information the Reynolds number was calculated to be 1655. Determine the Head drop if the pipe is 100 m in length. Hint: For laminar flow the fanning friction factor can be calculated as 16/Re 4 fLū² hs 2gD 2 Answer: Answer