By using the attached correlation tables for H1 NMR, calculate the expected hydrogen shifts (each one)of propiophenone and coumarin(show each step of calculations). Write what table are you using and which hydrogen is it ..labeled as (A, B,C etc). Then, Compare with the attached observed hydrogen shifts from the spectra..
By using the attached correlation tables for H1 NMR, calculate the expected hydrogen shifts (each one)of propiophenone and coumarin(show each step of calculations). Write what table are you using and which hydrogen is it ..labeled as (A, B,C etc). Then, Compare with the attached observed hydrogen shifts from the spectra..
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Question
By using the attached correlation tables for H1 NMR, calculate the expected hydrogen shifts (each one)of propiophenone and coumarin(show each step of calculations). Write what table are you using and which hydrogen is it ..labeled as (A, B,C etc).
Then, Compare with the attached observed hydrogen shifts from the spectra..
![The structure of the compound:
a
There is possibility of 5 signals in the NMR
spectrum.
Peaks
Ha
Hb
Hc
Hd
He
Ha
Hb
Hc
Hd
He
propiophenone
Hf
Chemical
Shift
Peaks
The structure of the compound is:
e H
1.18 ppm triplet
3.0 ppm
quartet
2H
7.97 ppm doublet 2H
7.53 ppm multiplet 2H
7.63 ppm triplet 1H
Multiplicity Integration
a H.
3H
H
b
H
There is 6 signals in the NMR spectrum.
Chemical
Multiplicity Integration
Shift
6.42 ppm doublet
1H
7.8 ppm doublet
1H
7.5 ppm
doublet 1H
7.28 ppm multiplet 1H
7.53 ppm multiplet
1H
7.32 ppm doublet 1H
a
coumarin](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fc4436f5f-01e3-4d46-baa5-3f23cf388ae7%2F14c7abb8-8c3d-488f-8793-2ffa751f1d6c%2Fqqxotm8_processed.jpeg&w=3840&q=75)
Transcribed Image Text:The structure of the compound:
a
There is possibility of 5 signals in the NMR
spectrum.
Peaks
Ha
Hb
Hc
Hd
He
Ha
Hb
Hc
Hd
He
propiophenone
Hf
Chemical
Shift
Peaks
The structure of the compound is:
e H
1.18 ppm triplet
3.0 ppm
quartet
2H
7.97 ppm doublet 2H
7.53 ppm multiplet 2H
7.63 ppm triplet 1H
Multiplicity Integration
a H.
3H
H
b
H
There is 6 signals in the NMR spectrum.
Chemical
Multiplicity Integration
Shift
6.42 ppm doublet
1H
7.8 ppm doublet
1H
7.5 ppm
doublet 1H
7.28 ppm multiplet 1H
7.53 ppm multiplet
1H
7.32 ppm doublet 1H
a
coumarin
![752
OH
-CH3
C
Substituent
Substituent
-R (alky)
0.9
-NH₂
-C-C
1.6
-NHCH 2.8
-C=C
1.8
_NH CO-R 2.8
-C₂H₁
2.3 N
-NR₂
-NH₂
-CO-NR₂
20
-NO₂
100
-CO-OR
2.0
C=O -CO-OH
2.1 S -SH
-CO-R
2.1
-SR
COH
2.2
-OR
-CO-C.H
2.6
-OH
-C=N
2.2
-O-C₂Hs
2.2
-D-CO-CH.
2.7
3.1
4.3
OH
Table 33.3 Chemical Shifts of Methyl Groups Attached to
Different Substituents
с
X
UNIT 33• NUCLEAR MAGNETIC RESONANCE
8 table
R stands for any alkyl group
C
C=O
X
base
-H (trans)
-CH₂OH (cis)
-CH5 (gem)
total
Jobs = 6.62 ppm
CH, CH-COOCH3
CH₂CH=CH₂
OCH3
alkynes
-1
-Br
-C
-F
-CO-NR₂
-CO-OR
attached to-C6Hs
8 table = 2.3 ppm
(8 obs=2.35 ppm)
ACH₂)-1.25 ppm + x +oy
-H
-R (alkyl)
-CH₂-C₂H₂
-CH₂OR
-C=C
-C-C (conj.)
-C=C
-C.Hs
R is any alkyl group.
Substituent
aldehydes
-R (alky)
-C-C
-CHC
-GH₂
-1
-Br
-C
-CO-OR
-CO-OH
-CO-NR₂
-CO-R-CO-H
-CO-GH₂
base
Table 33.4 Shielding Constants of Substituents Attached to Methylene and
Methine Groups
-C=N
total
X-CH₂-Y
Substituent
-OH
C=O-CO-OR (conj.)
-CO-OH
-CO-OH (conj.)
-CO-R
-CO-H
Example of the use of Table 33.3
base
-CO-OR
5.28 ppm
0
-0.02 ppm
1.43 ppm
6.69 ppm
total
-CcHs
-C=C
Stable
0
1.50 ppm
0.7 ppm
21 ppm
4.3 ppm
Jobs = 4.22 ppm
2
Stable
pem
0.98
1.26
0.50
1.43
CH₂-
3.35 ppm
Jobs = 3.39 ppm
1.37
0.84
0.68
1.00
0.69
1.10
1.03
H
e
0.0
0.8
0.9
13
0.7
0.8
1.0
1.2
1.6
1.2
1.4
1.9
20
1.25 ppm
1.3 ppm
0.8 ppm
Z
-5.28 ppm+++
0 0
0.44 -0.26 -0.29
1.05 -0.29 -0.32
0.67 -0.02 -0.07
-0.04 -0.21
0.08 -0.01
Table 33.5 Shielding Constants of Substituents Attached to Alkenes
Example of the use of Table 33.4
Methylene
8
An example of how to use Table 33.5 is given below.
attached to-CO-OR
å table=2.0 ppm
(8 obs=2.0 ppm)
N
0.35 0.10
0.39 0.06
S
O
total
=0
O
-O-CO-R
Methine
X
'OCH3
X-CH-Y
I
Z
(CH) 1.50 ppm + x + ax + o₂
1.7-1.8
R-C=C-H
Ar-C=C-H
R-C=C-H
R-C=C-C=C-H
aliphatic: R-CO-H
28-32
2.7-3.1
1.8-2.0
9-10
aromatic: Ar-CO-H 9.6-10.5
Ar is any aryl group: R" has at least a double bond in conjugation.
-OR
-OH
base
N
S
"For systems where the alkene, the substituent, or both are conjugated.
R stands for any alkyl group.
8 table
base
1.50 ppm
3-C6H5 3x1.3 ppm
1
Substituent
_NH::-NHR NR
_NH CH.
-NH-CO-R
-NO₂
-SH:-SR
H
-O-CH
-O-CO-R
-D-COCH,
1.25 ppm
-CO-OR 0.7 ppm
Cl
2.0 ppm
total
0.93 0.35
1.15 0.56
1.02 0.33
1.35 0.74
-OR
0.97 0.39 O -OC₂H₂
1.13 0.81
0.97 1.21
8 table
-C=N
-1
-Br
-a
-F
Substituent
2.5
5.4 ppm
Jobs = 5.55 ppm
3.2
CH₂OH
Table 33.7 Chemical Shift of Hydrogens on Unsaturated Carbons
Compound
2.6
Example of the use of Table 33.5
4.3
-O-CO-R
2.0
3.95 ppm
Jobs = 4.10 ppm
2.1
3.2
3.4
3.7
3.7
3.9
“NH:: -NHR NK:
-NH-CH
-NH-CO-R
-NO₂
-SH:-SR
33.14 CHEMICAL
Compound
Formates: RO-CO-H
Formamides: R₂N-CO-H
Imines: R-N-CRH
Alkenes: C-C-H
Aromatics: Ar-H
attached to-O-CO-R
& table = 3.7 ppm
(obs=3.6 ppm)
pm
0.23
&
1.14
1.04
1.00
1.54
8 table
8-82
8-87
1.00
•
1.0
1.8
2.1
3.2
1.3
base
-H (trans)
-CH₂OH (gem)
-C6H5 (cis)
total
8obs = 6.37 ppm
6-8
Table 33.5
Table 33.6
1.9
2.1
2.7
2.7
2.9
CICH₂COOCH,
0.69 -1.19 -1.31
-0.73 -0.81
2.30
2.08
-0.57 -0.72
0.62
1.87
1.32
-0.24 -0.04
CH
0.78
0.58
0.81 0.88
0.55
0.40
0.03
0.19
-0.40 -1.02
-1.06 -1.28
1.18
1.14 -0.65-1.05
-0.40 -0.67
2.09
5.28 ppm
0
0.67 ppm
0.39 ppm
6.34 ppm](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fc4436f5f-01e3-4d46-baa5-3f23cf388ae7%2F14c7abb8-8c3d-488f-8793-2ffa751f1d6c%2Fzvbxo5o_processed.jpeg&w=3840&q=75)
Transcribed Image Text:752
OH
-CH3
C
Substituent
Substituent
-R (alky)
0.9
-NH₂
-C-C
1.6
-NHCH 2.8
-C=C
1.8
_NH CO-R 2.8
-C₂H₁
2.3 N
-NR₂
-NH₂
-CO-NR₂
20
-NO₂
100
-CO-OR
2.0
C=O -CO-OH
2.1 S -SH
-CO-R
2.1
-SR
COH
2.2
-OR
-CO-C.H
2.6
-OH
-C=N
2.2
-O-C₂Hs
2.2
-D-CO-CH.
2.7
3.1
4.3
OH
Table 33.3 Chemical Shifts of Methyl Groups Attached to
Different Substituents
с
X
UNIT 33• NUCLEAR MAGNETIC RESONANCE
8 table
R stands for any alkyl group
C
C=O
X
base
-H (trans)
-CH₂OH (cis)
-CH5 (gem)
total
Jobs = 6.62 ppm
CH, CH-COOCH3
CH₂CH=CH₂
OCH3
alkynes
-1
-Br
-C
-F
-CO-NR₂
-CO-OR
attached to-C6Hs
8 table = 2.3 ppm
(8 obs=2.35 ppm)
ACH₂)-1.25 ppm + x +oy
-H
-R (alkyl)
-CH₂-C₂H₂
-CH₂OR
-C=C
-C-C (conj.)
-C=C
-C.Hs
R is any alkyl group.
Substituent
aldehydes
-R (alky)
-C-C
-CHC
-GH₂
-1
-Br
-C
-CO-OR
-CO-OH
-CO-NR₂
-CO-R-CO-H
-CO-GH₂
base
Table 33.4 Shielding Constants of Substituents Attached to Methylene and
Methine Groups
-C=N
total
X-CH₂-Y
Substituent
-OH
C=O-CO-OR (conj.)
-CO-OH
-CO-OH (conj.)
-CO-R
-CO-H
Example of the use of Table 33.3
base
-CO-OR
5.28 ppm
0
-0.02 ppm
1.43 ppm
6.69 ppm
total
-CcHs
-C=C
Stable
0
1.50 ppm
0.7 ppm
21 ppm
4.3 ppm
Jobs = 4.22 ppm
2
Stable
pem
0.98
1.26
0.50
1.43
CH₂-
3.35 ppm
Jobs = 3.39 ppm
1.37
0.84
0.68
1.00
0.69
1.10
1.03
H
e
0.0
0.8
0.9
13
0.7
0.8
1.0
1.2
1.6
1.2
1.4
1.9
20
1.25 ppm
1.3 ppm
0.8 ppm
Z
-5.28 ppm+++
0 0
0.44 -0.26 -0.29
1.05 -0.29 -0.32
0.67 -0.02 -0.07
-0.04 -0.21
0.08 -0.01
Table 33.5 Shielding Constants of Substituents Attached to Alkenes
Example of the use of Table 33.4
Methylene
8
An example of how to use Table 33.5 is given below.
attached to-CO-OR
å table=2.0 ppm
(8 obs=2.0 ppm)
N
0.35 0.10
0.39 0.06
S
O
total
=0
O
-O-CO-R
Methine
X
'OCH3
X-CH-Y
I
Z
(CH) 1.50 ppm + x + ax + o₂
1.7-1.8
R-C=C-H
Ar-C=C-H
R-C=C-H
R-C=C-C=C-H
aliphatic: R-CO-H
28-32
2.7-3.1
1.8-2.0
9-10
aromatic: Ar-CO-H 9.6-10.5
Ar is any aryl group: R" has at least a double bond in conjugation.
-OR
-OH
base
N
S
"For systems where the alkene, the substituent, or both are conjugated.
R stands for any alkyl group.
8 table
base
1.50 ppm
3-C6H5 3x1.3 ppm
1
Substituent
_NH::-NHR NR
_NH CH.
-NH-CO-R
-NO₂
-SH:-SR
H
-O-CH
-O-CO-R
-D-COCH,
1.25 ppm
-CO-OR 0.7 ppm
Cl
2.0 ppm
total
0.93 0.35
1.15 0.56
1.02 0.33
1.35 0.74
-OR
0.97 0.39 O -OC₂H₂
1.13 0.81
0.97 1.21
8 table
-C=N
-1
-Br
-a
-F
Substituent
2.5
5.4 ppm
Jobs = 5.55 ppm
3.2
CH₂OH
Table 33.7 Chemical Shift of Hydrogens on Unsaturated Carbons
Compound
2.6
Example of the use of Table 33.5
4.3
-O-CO-R
2.0
3.95 ppm
Jobs = 4.10 ppm
2.1
3.2
3.4
3.7
3.7
3.9
“NH:: -NHR NK:
-NH-CH
-NH-CO-R
-NO₂
-SH:-SR
33.14 CHEMICAL
Compound
Formates: RO-CO-H
Formamides: R₂N-CO-H
Imines: R-N-CRH
Alkenes: C-C-H
Aromatics: Ar-H
attached to-O-CO-R
& table = 3.7 ppm
(obs=3.6 ppm)
pm
0.23
&
1.14
1.04
1.00
1.54
8 table
8-82
8-87
1.00
•
1.0
1.8
2.1
3.2
1.3
base
-H (trans)
-CH₂OH (gem)
-C6H5 (cis)
total
8obs = 6.37 ppm
6-8
Table 33.5
Table 33.6
1.9
2.1
2.7
2.7
2.9
CICH₂COOCH,
0.69 -1.19 -1.31
-0.73 -0.81
2.30
2.08
-0.57 -0.72
0.62
1.87
1.32
-0.24 -0.04
CH
0.78
0.58
0.81 0.88
0.55
0.40
0.03
0.19
-0.40 -1.02
-1.06 -1.28
1.18
1.14 -0.65-1.05
-0.40 -0.67
2.09
5.28 ppm
0
0.67 ppm
0.39 ppm
6.34 ppm
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