Please give Experts solution only with explanation and step by step 2. Draw the expected proton coupled 13C spectrum of benzene.

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Answered: 2. Draw the expected proton coupled 13C…

Organic Chemistry: A Guided Inquiry

2nd Edition

ISBN:9780618974122

Author:Andrei Straumanis

Publisher:Andrei Straumanis

ChapterL4: Proton (1h) Nmr Spectroscopy

Section: Chapter Questions

Problem 15E

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Similar questions

1B. Can 1H NMR spectroscopy be used to differentiate between the two compounds? Briefly explain why or why not. Predict the 1H NMR spectrum for each compound (include integration, multiplicity, and approximate chemical shift). Put it in data table format.
Why do aldehydes, esters, and amides all have a strong absorption in the 1630-1780 cm1 region of their IR spectra? A) The bond between H and the sp³-hybridized C in these functional groups vibrates in this energy range. B) Each of these functional groups has at least two resonance structures, and the different vibrations of the resonance structures give off energy in this region. C) The bond between O and the sp²-hybridized C in these functional groups vibrates at a frequency in this energy range. D) Light at this wavenumber causes the average C to O bond length to increase which causes more of this light to be transmitted. E) An electron in the bond of these functional groups gets excited to the * orbital.
Answer and explain in detail how you arrived at that answer.
6) Complete the spectroscopy data tables for a compound with molecular formula C6H12O. Determine the structure of the compound. Any labile protons, if they exist, will not be present in this particular 1H NMR spectrum.
7. How could you distinguish between 1-butanol and diethyl ether by infrared spectroscopy? 1-butanol OH both C4H10O 8. How could you distinguish between methyl butanoate and pentanoic acid by infrared spectroscopy? ha pentancic acid diethyl ether OH both CsH100 OCH3 methyl butanoate
Question 9 of 18 Match the peaks in this spectrum with the carbons on the structure below. A) : 178.1 рpm II: 68.8 ppm III: 22.5 ppm IV: 27.9 ppm B) I: 178.1 ppm II: 22.5 ppm I: 68.8 рpm IV: 27.9 ppm 160 C) I: 178.1 ppm O. II: 27.9 ppm III IV II: 22.5 ppm IV: 68.8 ppm D) I: 68.8 ppm II: 27.9 ppm II: 22.5 ppm IV: 178.1 ppm
what is the constitutional isomer for this spectrum? (C5h12O)
The DEPT-90 spectrum exhibits 6 in the 0-50 ppm region The DEPT-135 spectrum exhibits x 100 ppm region that is a positive ▾ C6 signal(s) for the CH groups: ▼ 1,2,6 ✓ in the sp2 hybridized region 100-150 C3 and C4 ▼ signal(s) (only the quaternary carbon atoms, signal(s), indicating the presence of a methylene group (CH₂) attached to an oxygen atom, are missing); there is C5 ▼ C1 and C2 ▼ and signal(s) in the 50-
Which of the following would not theoretically be seen in the splitting patterns for the 1Hb NMR signals for the following molecule if Jab < Jbc . CH; „Hb H;aC `CH2c-Br A. type b splits type a into a doublet B. type b splits type c into a doublet O C. type a splits type b into a septet then type c splits those into triplets O D. type c splits type b into a triplet then type a splits those into septets
11. Predict the number of signals expected in the 13C spectrum of a. 1-bromo-2-chlorobenzene b. 1-bromo-4-chlorobenzene
13. The molecular formula of the compound responsible for the below spectrum is C9H20. What is its structural formula? 3 N PPM 2H 3H IHD= 2(9)+2-20 2
Here are proton NMR data for 1-bromopropane: Ha : triplet (2H) 3.32ppm; Hb : multiplet (2H)1.81ppm; Hc : triplet (3H) 0.93ppm. (Relative integrations shown in parentheses.) a. Through how many bonds can a hydrogen split another hydrogen? b. According to this splitting rule, does Ha split Hc ? c. Is your answer in part a) consistent with the multiplicity listed for peak clusters a and c? d. How many hydrogenssplit Hb ? e. Upon very close inspection of the proton NMR spectrum of 1-bromopropane, you wouldfind that peak cluster b has at least six peaks. Is this consistent with your answer in part d)? f. Speculate as to why any peak cluster with more than four peaks is listed simply as a"multiplet."

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