By the inductive hypothesis and the definition of divisibility, there exists an integer r such that 7k – 2k = 5r. Then 7k + 1 - 2k + 1 = 7 · 7k – 2· 2k = (5 + 2) · 7k – 2 · 2k. Continue simplifying the right-hand side of the equation, apply the induction hypothesis, and express the result in terms of k and r. 7k + 1- 2k + 1 - 5 . zk + 2r This quantity ic an inf

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